在嵌套的python字典中设置一个值，给出索引和值的列表

问题描述

对不起，如果这个问题已经得到回答，我一直在寻找解决方案，但我可能没有使用正确的搜索字词。

Sorry if this question has been answered before - I've been searching for solutions but I maybe am not using the correct search terms.

无论如何，尝试做的是以编程方式设置字典中的值，可能嵌套，给​​出索引列表和值。

Anyway, what I'm trying to do is to programmatically set a value in a dictionary, potentially nested, given a list of indices and a value.

所以例如，我的列表索引是：

So for example, let's say my list of indices is:

['person', 'address', 'city'] 

，值为

'New York'

我想要一个字典对象，如：

I want as a result a dictionary object like:

{ 'Person': { 'address': { 'city': 'New York' } }

基本上，列表表示嵌套字典中的路径。

Basically, the list represents a 'path' into a nested dictionary.

我认为我可以构建字典本身，但是我绊倒的是如何设置值。显然，如果我只是手动编写代码，那将是：

I think I can construct the dictionary itself, but where I'm stumbling is how to set the value. Obviously if I was just writing code for this manually it would be:

dict['Person']['address']['city'] = 'New York'

但是，如何索引到字典并设置值像编程方式，如果我只是有一个索引和值的列表？

But how do I index into the dictionary and set the value like that programmatically if I just have a list of the indices and the value?

希望这是有道理的，不是太笨的问题... :)谢谢你任何帮助。

Hope this makes sense and isn't too dumb a question... :) Thanks for any help.

推荐答案

这样的事情可以帮助：

def nested_set(dic, keys, value):
    for key in keys[:-1]:
        dic = dic.setdefault(key, {})
    dic[keys[-1]] = value

你可以这样使用： p>

And you can use it like this:

>>> d = {}
>>> nested_set(d, ['person', 'address', 'city'], 'New York')
>>> d
{'person': {'address': {'city': 'New York'}}}

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