LINQ：选择从不同的LST并附加不同的属性到一个

问题描述

我有以下问题，其中我想寻求帮助。我有（由一个属性条件）来选择不同的值，然后从属性的其余部分中提取不同的值。

I have the following problem, in which I would like to ask for help. I have to select distinct values(criteria by one property) and then extract the different values from the rest of the properties.

让我们说，我有下面的类，其中每个 BOM 有一个或多个 FlatComponents 不同的配件和 QtyPer 。

Let's say that I have the following class in which each BOM has one or more FlatComponents with different Parts and QtyPer.

例如：

public sealed class BOM {
    public string FlatComponent {
        get;
        set;
    }

    public string Part {
        get;
        set;
    }

    public string QtyPer {
        get;
        set;
    }

    public BOM(String flatComponent, String part, String qtyPer) {
        this.FlatComponent=flatComponent;
        this.Part=part;
        this.QtyPer=qtyPer;
    }
}

List<BOM> list=new List<BOM>();
list.Add(new BOM("a", "1", "2"));
list.Add(new BOM("a", "3", "4"));
list.Add(new BOM("b", "5", "6"));
list.Add(new BOM("c", "7", "8"));
list.Add(new BOM("c", "9", "0"));

我将如何选择不同的 FlatComponents 及其在使用LINQ（以逗号分隔），每个属性值diferent？

How would I select distinct FlatComponents and its diferent values in each property using LINQ(separated by comma)?

Result = [
    ["a", "1, 3", "2, 4"],
    ["b", "5", "6"],
    ["c", "7, 9", "8, 0"]
    ]

我已经尝试使用 .Distinct（），但我与LINQ很新...

I have tried using .Distinct(), but I am pretty new with LINQ ...

推荐答案

试试这个：

var result = list
    .GroupBy(e => e.FlatComponent)
    .Select(e => new BOM
        {
            FlatComponent = e.Key,
            Part = string.Join(", ", e.Select(x => x.Part)),
            QtyPer = string.Join(", ", e.Select(x => x.QtyPer))
        });

这将创建一个独特的 BOM 每个 FlatComponent 与<$加入部分和 QtyPer 属性C $ C>，。

It will create a distinct BOM for each FlatComponent, joining the Part and QtyPer properties with ", ".

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