问题描述
我已经将头撞在墙上一个多小时了，我不明白为什么下面的方法不起作用.如果我将 b:db 1 更改为 b:db 0 ，则它应打印10，否则应打印0.相反，程序始终打印10.
I've been bashing my head against the wall for over an hour and I can't understand why the below doesn't work.If I change b: db 1 to b: db 0 then it should print 10, otherwise it should print 0. Instead, the program always prints 10.
我一直在写一个编写程序集的项目，这是失败的单元测试之一，我只是不明白.它必须很简单.
I've been writing a project that writes assembly and this is one of the unit test that fails and I just don't get it. It has to be something simple.
extern printf, exit
section .bss
section .data
b: db 1
x: dd 5
y: dd 5
z: dd 0
int_pattern: db "%i", 10, 0
global main
section .text
main:
mov eax, dword [b]
cmp eax, dword 0
je condition_end4
; add x and y
; store into z
mov eax, dword [rel x]
add eax, dword [rel y]
mov [rel z], eax
condition_end4:
; rsi = &z
; rdi = &int_pattern
mov rsi, qword [z]
mov rdi, int_pattern
; not using vector registers
xor rax, rax
; printf(int_pattern, z);
call printf
我正在将Debian Linux和NASM一起使用.组装/链接
I'm using Debian Linux with NASM. Assembling/linking with
nasm -f elf64 -o test.o test.asm
gcc test.o -o test.bin
即使 b 为0，GDB也会显示 cmp 取消ZF设置，因此我对此感到茫然.
Even when b is 0, GDB shows that the cmp unsets ZF so I'm at a loss here.
谢谢！
推荐答案
您已将 b 声明为一个字节:
You've declared b as a byte:
b: db 1
但您将其作为双字加载:
but you load it as a dword:
mov eax, dword [b]
这说明了为什么即使b为0时也不会设置零标志:因为它也正在加载接下来的3个字节.
This explains why the zero flag is unset even when b is 0: because it's loading the next 3 bytes as well.
只需更改您的声明:
b: dd 1
或者，您可以加载扩展名为零的字节: movzx eax，字节[b]
Alternatively, you could load a byte with zero extension: movzx eax, byte [b]
类似地，您从 z 加载了一个qword，但仅将其定义为 dd dword.请参阅要使用的变量大小(db，dw，dd)使用x86汇编程序?
Similarly, you load a qword from z but you only defined it as a dd dword. See Which variable size to use (db, dw, dd) with x86 assembly?
此外，使用 default rel ，以便所有寻址模式都选择相对于RIP的寻址，而不必到处都说 [rel b] .
Also, use default rel so all addressing modes pick RIP-relative addressing without having to say [rel b] everywhere.
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