根据深层阵列中任何地方存在的特定键制作唯一的值列表

问题描述

我有一个数组，该数组递归地(n层深)由不确定数量的数组组成.每个数组可能包含一个name键.我想为这些值创建一个唯一列表.

I have an array that consists of an undetermined number of arrays, recursively (n levels deep). Each array might contain a name key. I want to create a unique list of those values.

示例

假设数组为:

$bigArray = array(
    'name'=>'one', 
    'something'=>array(
        'name'=>'two', 
        'subthing'=>array('name'=>'three')
    ), 
    'anotherthing'=>array('name'=>'one')
);

预期结果将是:

$uniques = array('one', 'two', 'three') // All the 'name' keys values and without duplicates.

这是一个我的尝试很简单.

我的方法是使用array_walk_recursive传递$uniques数组作为参考，并允许函数更新该值:

My approach was using array_walk_recursive passing a $uniques array as reference, and allowing the function to update that value:

$uniques = array();

function singleOut($item, $key, &$uniques) {
    if ($key == 'name' && !in_array($itm,$uniques,true) )
        $uniques[] = $item;
}

array_walk_recursive($bigArray, 'singleOut', $uniques);

但是，它对我不起作用.

However, it's not working for me.

推荐答案

您也可以在此计算机上使用array_unique.示例:

You could use also array_unique on this one too. Example:

$uniques = array();
array_walk_recursive($bigArray, function($val, $key) use (&$uniques){
    if($key == 'name') {
        $uniques[] = $val;
    }
});

$uniques = array_unique($uniques); // unique values

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