本文介绍了文件上传不使用任何ASP控制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想上传一张图片,而无需使用任何asp的控件。到目前为止,我一直在想:

I'm trying to upload an image without using any of the asp controls. So far I've been trying:

        <form id="form1" data-ajax="false" method="post" runat="server" enctype="multipart/form-data">
            <input type="file" id="uploadFile" name="uploadFile" runat="server"/>
            <input type="submit" class="btn-login" data-corners="true" value="Yükle" onclick="UploadPhoto()" />
        </form>

在我的.aspx页面,并在UploadPhoto()的JQuery的方法:

in my .aspx page and in UploadPhoto() method in JQuery:

function UploadPhoto() {
            $.ajax({
                type: "POST",
                url: "IncidentChange.aspx/UploadPhoto",
                contentType: "application/json; charset=utf-8",
                success: function (msg) {
                },
                error: function () {
                }
            });
        }

我张贴到C#code后面。但是,我无法从codebehind达到上传的项目。

I am posting to C# code behind. However, I could not reach the uploaded item from codebehind.

        [WebMethod]
        public static string UploadPhoto()
        {
            try
            {
                byte[] fileData = null;
                using (var binaryReader = new BinaryReader(HttpContext.Current.Request.Files[0].InputStream))
                {
                    fileData = binaryReader.ReadBytes(HttpContext.Current.Request.Files[0].ContentLength);
                }

            }
            catch (Exception ex)
            {
            }
            return null;
        }

然而Request.Files似乎是一个空数组。由于该方法是静态的([WebMethod的])我不能在法内到达输入控制,以获得发布的文件。我怎样才能解决这个问题?谢谢你。

However Request.Files appears to be a null array. Since the method is static ([WebMethod]) I cannot reach the input control within the method to get the posted file. How can I overcome this issue? Thank you.

推荐答案

HTML:

<input type="file" id="uploadFile" name="uploadFile"/>
<input type="button" id="submit" value="Submit" onClick="UploadFile();"/> 

JQuery的:

 <script type="text/javascript">
$(document).ready(function () {
        function UploadFile() {
    var fileName = $('#uploadFile').val().replace(/.*(\/|\\)/, '');
                       if (fileName != "") {
                        $.ajaxFileUpload({ url: 'AjaxFileUploader.ashx',
                            secureuri: false,
                            fileElementId: 'uploadFile',
                            dataType: 'json',
                            success: function (data, status) {
                               if (typeof (data.error) != 'undefined') {
                        if (data.error != '') {
                            alert(data.error);
                        } else {
                            alert('Success');
                        }
                    }
                },
                  error: function (data, status, e) {
                                alert(e);
                            }
                        }
                        )
                    }
}
});

请从tyhe bekow链接下载AJAX文件上传插件。

Please download ajax file uploader plugin from tyhe bekow link.

http://www.phpletter.com/DOWNLOAD/

处理程序:

    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Web;
    using System.IO;
    using System.Text.RegularExpressions;
    using System.Text;
 namespace MyProject
 {
   public class AjaxFileUploader : IHttpHandler
   {
    {

        public void ProcessRequest(HttpContext context)
        {

            if (context.Request.Files.Count > 0)
            {
                string path = context.Server.MapPath("~/UploadImages");
                if (!Directory.Exists(path))
                    Directory.CreateDirectory(path);

                var file = context.Request.Files[0];

                string fileName;

                if (HttpContext.Current.Request.Browser.Browser.ToUpper() == "IE")
                {
                    string[] files = file.FileName.Split(new char[] { '\\' });
                    fileName = files[files.Length - 1];
                }
                else
                {
                    fileName = file.FileName;
                }
                string newFilename = Guid.NewGuid().ToString();
                FileInfo fInfo = new FileInfo(fileName);
                newFilename = string.Format("{0}{1}", newFilename, fInfo.Extension);
                string strFileName = newFilename;
                fileName = Path.Combine(path, newFilename);
                file.SaveAs(fileName);


                string msg = "{";
                msg += string.Format("error:'{0}',\n", string.Empty);
                msg += string.Format("msg:'{0}'\n", strFileName);
                msg += "}";
                context.Response.Write(msg);


            }
        }

        public bool IsReusable
        {
            get
            {
                return true;
            }
        }
    }
}

这篇关于文件上传不使用任何ASP控制的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-30 00:49