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问题描述

我似乎无法使用一个基类作为一个函数参数,我搞砸了我的继承?

I seem to be unable to use a base class as a function parameter, have I messed up my inheritance?

我在我的主要有以下:

int some_ftn(Foo *f) { /* some code */ };
Bar b;
some_ftn(&b);

而且继承自Foo的类Bar也是这样:

And the class Bar inheriting from Foo in such a way:

class Bar : Foo
{
public:
    Bar();
    //snip

private:
    //snip
};

这不行吗?我似乎不能在我的主要功能中进行调用

Should this not work? I don't seem to be able to make that call in my main function

推荐答案

您必须这样做:

class Bar : public Foo
{
    // ...
}

C ++中的默认继承类型为 private ,所以任何 public protected private struct 另一方面,继承默认为 public

The default inheritance type of a class in C++ is private, so any public and protected members from the base class are limited to private. struct inheritance on the other hand is public by default.

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10-30 00:10