问题描述
我已经搜索了一下,但是我无法找到一种以编程方式从XML Schema自动生成数据的方法.可以说我有这个XML模式:
I have searched for a bit now, but i'm not able to find a way to autogenerate data from a XML Schema programmatically. Lets say I have this XML schema:
<xs:element xmlns:xs="http://www.w3.org/2001/XMLSchema" name ="Persons">
<xs:complexType>
<xs:sequence>
<xs:element name="Person">
<xs:complexType>
<xs:sequence>
<xs:element name="FirstName" type="xs:string" />
<xs:element name="LastName" type="xs:string" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
我可以使用VS函数"Generate Sample XML"从中创建XML
有没有办法通过编程方式做到这一点?
I am able to create a XML from this using the VS function "Generate Sample XML"
Is there a way to do this programmatically?
指定.我不想自己创建所有对象并以编程方式插入数据.我希望它像VS中的"Generate Sample XML"一样自动创建对象和属性.原因是我想更改XSD,而不必对xml样本生成做任何事情.
To specify. I do not want to create all the objects and insert data programmatically myself. I would like for it to create the objects and attributes automatically just like the "Generate Sample XML" in VS. The reason for this is that i would like to change the XSD without having to do anything about xml sample generation.
推荐答案
.我发现一个实现了xml示例生成器的项目.我创建了一个测试解决方案,并导入了这些类.然后,我删除了XmlGen.cs文件并创建了自己的主方法.输出将基于根元素.
after doing some searching. I have found a project that have implemented a xml sample generator. I created a test solution and imported the classes. Then i deleted the XmlGen.cs file and created my own main method. The output will be based on the root element.
public static void Main(string[] args)
{
using (var stream = new MemoryStream(File.ReadAllBytes("schema.xsd")))
{
var schema = XmlSchema.Read(XmlReader.Create(stream ), null);
var gen = new XmlSampleGenerator(schema, new XmlQualifiedName("rootElement"));
gen.WriteXml(XmlWriter.Create(@"c:\temp\autogen.xml"));
Console.WriteLine("Autogenerated file is here : c:\temp\autogen.xml");
}
}
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