RSA ... GNU MP：无法分配内存（大小= 1307836444）

本文介绍了RSA ... GNU MP：无法分配内存（大小= 1307836444）的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 首先，我运行Ubuntu 12.04 32位。此程序通过将 cin 添加到字符缓冲区中来执行RSA公钥密钥加密。然后，当我调用我的加密功能，我得到以下错误：To start, I'm running Ubuntu 12.04 32-bit. This program does RSA pub key crypto by taking cin into a char buffer. Then, when I call my encrypt function, I get the following error:GNU MP: Cannot allocate memory (size=1307836444)Aborted (core dumped)当我更改键生成，这个运行时错误的大小增加。此错误仅在我调用 encrypt（）后发生。void generate_pq(mpz_t p, mpz_t q);void compute_n(mpz_t n, const mpz_t p, const mpz_t q);void compute_phiN(mpz_t phi_n, const mpz_t p, const mpz_t q);void select_e(mpz_t e, mpz_t phi_n);void compute_d(mpz_t d, mpz_t e, mpz_t phi_n);void store_m(mpz_t m[], int& size);void encrypt(mpz_t c[], mpz_t m[], const int size, const mpz_t e, const mpz_t n);void decrypt(mpz_t m2[], mpz_t c[], const int size, const mpz_t d, const mpz_t n);int main() { mpz_t p, q, n, phi_n, e, d; mpz_inits(p, q, n, phi_n, e, d, NULL); // 1. Generate p,q; compute n generate_pq(p,q); compute_n(n,p,q); // 2. Compute phi(n)=(p-1)*(q-1) compute_phiN(phi_n,p,q); mpz_clear(p); mpz_clear(q); // 3. Select encryption key e select_e(e,phi_n); // 4. Compute decryption key d compute_d(d,e,phi_n); // 5. m = message to be encrypted mpz_t* m; int size=0; store_m(m,size); // 6. c = encrypted message mpz_t* c; encrypt(c,m,size,e,n); // 7. m2 = decrypted message //mpz_t* m2; //decrypt(m2,c,size,d,n); return 0;}使用...编译g++ -o rsa partb.cc -lgmpxx -lgmp我已经尝试过在m，c和m2的for循环中使用mpz_clear。不用找了。这里是加密函数：I have tried using mpz_clear in the for-loops for m, c, and m2. No change. Here is the encrypt function:void store_m(mpz_t m[], int& size) { printf("Message: "); char* buffer = new char[128]; cin.getline(buffer,128); size = strlen(buffer); //size = buffer m = new mpz_t[size]; for(int i=0; i<size; i++) { mpz_init(m[i]); mpz_set_ui(m[i],(int)buffer[i]); }}void encrypt(mpz_t c[], mpz_t m[], const int size, const mpz_t e, const mpz_t n){ /* c = cipher */ c = new mpz_t[size]; for(int i=0; i<size; i++) { mpz_init(c[i]); mpz_powm(c[i],m[i],e,n); mpz_clear(m[i]); } /* c = m^e(mod n) */}也许问题是，我不是释放足够的mpz_t我已经宣布和初始化？我尝试清除2或3的mpz_t的，但它似乎没有效果。请指教。Perhaps the issue is that I am not deallocating enough of the mpz_t's that I have declared and initialized? I tried clearing 2 or 3 of the mpz_t's but it didn't seem to have an effect. Please advise. 编辑!!!!!!!! 对此语句的seg fault：Isolated the seg fault to this statement:mpz_powm(c[i],m[i],e,n); 推荐答案您的变数 mpz_t * c encrypt 函数不更改，因此在 encrypt之后仍然指向随机（可能无效） code>返回。请改为尝试：Your variable mpz_t* c is not changed by the encrypt function, so it still points to a random (probably invalid) address after encrypt returns. Try instead: void encrypted（mpz_t *& c，... 这篇关于RSA ... GNU MP：无法分配内存（大小= 1307836444）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！