问题描述
我已经成立了一个ListView。每个在ListView项包含一个切换按钮,
这将启动或在服务停止线程。
I've set up a ListView. Each of the ListView-Items contains a ToggleButton,which starts or stops a Thread in a Service.
的线程需要只要的ToggleButtons被激活运行。如果活动停止,服务和激活的线程需要继续
The threads need to run as long as the toggleButtons are activated. If the activity stops, the service and the activated threads need to continue.
//In MainActivity
@Override
public void onCheckedChanged(CompoundButton buttonView,
boolean isChecked) {
Intent intent = new Intent(context,MyService.class);
intent.putExtra("id",listviewPosition);
startService(intent);
}
//MyService
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
// Thread(startId) starten
HandlerThread thread = new HandlerThread(String.valueOf(startId));
thread.start();
// Threads looper holen und beim servicehandler benutzen
serviceHandler = new ServiceHandler(thread.getLooper());
listServericeHandler.add(serviceHandler);
//message ausm pool holen
Message msg = serviceHandler.obtainMessage();
msg.arg1 = startId;
serviceHandler.sendMessage(msg);
return START_STICKY;
}
private final class ServiceHandler extends Handler {
public ServiceHandler(Looper looper) {
super(looper);
}
@Override
public void handleMessage(Message msg) {
while (continueUntilToggleButtonIsDeactivated) {
Log.d(MainActivity.TAG, "Thread " + tring.valueOf(msg.arg1)
+ " running: " + url.toExternalForm());
synchronized (this) {
try {
//do stuff
wait(1000);
} catch (Exception e) {
}
}
}
}
}
所以,我想我开始激活切换按钮的 OnStartCommand()
每次在一个线程中。
我不知道如何停止线程,并获得了while循环的。
What I don't know is how to stop the threads and get the out of the while-loop.
推荐答案
您只需要创建while循环一个标志,遵守知道什么时候停下来。例如:
You just need to create a flag for the while loop to abide by to know when to stop. For example:
private final class ServiceHandler extends Handler {
private volatile boolean _continueRunning = true;
public ServiceHandler(Looper looper) {
super(looper);
}
public void stopRunning() {
_continueRunning = false;
this.notify(); //Interrupts the wait
}
@Override
public void handleMessage(Message msg) {
while (_continueRunning) { //Watches the variable
Log.d(MainActivity.TAG, "Thread " + tring.valueOf(msg.arg1)
+ " running: " + url.toExternalForm());
synchronized (this) {
try {
//do stuff
wait(1000);
} catch (Exception e) {}
}
}
}
修改
您应该建立在服务的的onCreate()
方法您的处理程序。在 onStartCommand
方法会通知您的新邮件。
You should create your handler in the onCreate()
method of the service. The onStartCommand
method informs you of new messages.
//In your Service Class
...
private ServiceHandler _serviceHandler;
@Override
public void onCreate() {
HandlerThread thread = new HandlerThread("ServiceClassName");
thread.start();
// Threads looper holen und beim servicehandler benutzen
serviceHandler = new ServiceHandler(thread.getLooper());
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
//message ausm pool holen
Message msg = _serviceHandler.obtainMessage();
msg.arg1 = startId;
serviceHandler.sendMessage(msg);
return START_STICKY;
}
private class mRunnable implements Runnable {
private volatile boolean _continueRunning = true;
@Override
public void run() {
while (_continueRunning) { //Watches the variable
synchronized (this) {
try {
//do stuff
wait(1000);
} catch (Exception e) {
//Purposefully left blank
}
}
}
}
public void stopRunning() {
_continueRunning = false;
this.notify();
}
}
然后你改变你的ServiceHandler为
Then you change your ServiceHandler to
private final class ServiceHandler extends Handler {
//TODO whatever type of list you need
private List<mRunnable> _runningThreads = new LinkedList<mRunnable>();
public ServiceHandler(Looper looper) {
super(looper);
}
@Override
public void handleMessage(Message msg) {
mRunnable runnable = new mRunnable();
new Thread(runnable).start();
}
}
这篇关于Android的服务多线程的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!