如何将多个.txt文件腌制为一个腌制

问题描述

我需要克服一些cPickle的限制，也就是说，我需要打开多个文件并将它们腌制为一个文件，如下所示:

I need to overcome some cPickle constrains,namely i need to open several files and pickle them to one file, like this:

import cPickle

file1=open('file1.txt','r')
file2=open('file2.txt','r')
obj=[file1,file2] or obj=[file1.read(), file2.read()]
cPickle.dump(obj,open('result.i2','w'),2)

，以便稍后我可以重新选择"它们并获取数据.

so that later I can "repickle" them and get the data.

cPickle是这样做的好方法吗?如果是，我该如何正确地做到这一点

Is a cPickle good way to do so?If yes how can I do it properly

如果没有，什么合适?

预先感谢

Rafal

推荐答案

这是正确的方法，它将使文件内容腌制:

This is the correct way, it pickles the file contents:

file1=open('file1.txt','r')
file2=open('file2.txt','r')
obj=[file1.read(), file2.read()]
cPickle.dump(obj,open('result.i2','w'),2)

如果设置obj=[file1,file2]，则不是在腌制文件内容，而是在腌制文件句柄.

If you set obj=[file1,file2] you are not pickling the file contents, you are pickling the file handles.

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