如果进程停止，则在 Monit 中重新运行进程

问题描述

我有一个这样的脚本:

#!/usr/bin/php
<?php
file_put_contents('/home/vagrant/sleep.pid', getmypid());
sleep(9);
exit(0);

我想编写我的 Monit 配置，以确保此应用程序始终运行.这是我的监控配置:

I want to write my Monit config so it makes sure this application is always running. This is my monit config:

set daemon 5
check process program with pidfile /home/vagrant/sleep.pid
   start program = "/usr/bin/php /home/vagrant/myphp.php"

但是在我的程序退出后，Monit 不会尝试再次运行它.这有点道理，但我想知道是否有任何方法可以告诉 Monit 重新运行该过程.

But after my program exits Monit doesn't try to run it again. It kinda make sense but I was wondering if there is any way to tell Monit to rerun the process.

推荐答案

在与 Monit 玩了更多次之后，我发现我没有正确运行 Monit.

After playing around more with Monit, I found that I wasn't running Monit properly.

首先，您需要将以下配置添加到您的 monit 文件中:

First you need to add the following config to your monit file:

set httpd port 2812 and allow monit:monit
set daemon 5
check process program with pidfile /home/vagrant/sleep.pid
    start program = "/usr/bin/php /home/vagrant/myphp.php"

然后使用以下命令运行监视器:

Then run the monit with this command:

monit -c monit.conf

现在Monit在后台运行，如果它死掉了，你可以重新启动或启动特定的程序:

Now Monit runs in the background and rerun the process if it dies, you may restart or start specific program with :

monit -c monit.conf start all

或

monit -c monit.conf stop my_role

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