从拉跨域HTML元素

本文介绍了从拉跨域HTML元素的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我想拉某的div名为类=行设备毛利率-B50通过YQL，但它不拉的确切数据，如果我把的XPath =*，它带来的整个页面，但我需要一定的格在我结束请告诉我，我缺少什么呢？

 ＆LT;头=服务器＆GT;
        ＆LT;脚本SRC =jQuery的-2.1.4.js＆GT;＆LT; / SCRIPT＆GT;
    ＆LT; /头
    ＆LT;脚本＆GT;


        jQuery.ajax =（函数（_ajax）{

            VAR协议= location.protocol，
                主机名= location.hostname，
                exRegex =正则表达式（协议+'//'+主机名），
                YQL =HTTP+（/^https/.test(protocol）的'：''）+'？：？//query.yahooapis.com/v1/public/yql回调='，
                查询=SELECT * FROM HTML其中，url ={网址}和XPath =*';


            功能isExternal（URL）{
                返回exRegex.test（URL）及！＆安培; /:\/\//.test(url）;
            }

            复位功能（O）{

                VAR URL = o.url;

                如果（/get/i.test(o.type）及＆安培;！/json/i.test（o.dataType）及＆安培; isExternal（URL））{

                    //操纵选项，使JSONP-X请求发送到YQL

                    o.url = YQL;
                    o.dataType ='json的';

                    o.data = {
                        问：query.replace（
                            {网址}，
                            URL +（o.data？
                                （/\?/.test(url）'＆安培;'：？）+ jQuery.param（o.data）'？'
                            ：''）
                        ），
                        格式：XML
                    };


                    如果（o.success＆安培;！＆安培; o.complete）{
                        o.success = o.complete;
                        删除o.complete;
                    }

                    o.success =（函数（_success）{
                        返回功能（数据）{

                            如果（_success）{

                                _success.call（这一点，{
                                    responseText的：（data.results [0] ||''）
                                   .replace（/＆所述;脚本[^＆GT;] + \ /＆GT; |？＆所述;？脚本（| \多个）* \ /脚本＆GT; / GI，''）
                                }， '成功'）;
                            }

                        };
                    }）（o.success）;

                }

                返回_ajax.apply（这一点，参数）;

            };

        }）（jQuery.ajax）;

        $阿贾克斯（{
            网址：http://www.mtbc.com/about-us/$p$pss-room/，
            键入：GET，
            成功：函数（RES）{
                执行console.log（RES）;
                $（'＃内容）HTML（res.responseText）;
            }
        }）;

    ＆LT; / SCRIPT＆GT;

HTML标记

 ＆LT; DIV ID =内容＆GT;
    搜索....
    ＆LT; / DIV＆GT;

解决方案

请尝试使用：

 的XPath ='// DIV [含有（@class，排装置利润-B50）

这样，你应该只得到分度，你想要的类。

I want to pull the certain div named class="row device-margin-b50" through YQL but its not pulling the exact data if I put xpath="*", it brings the whole page but I need certain div at my end Whats I'm lacking?

 <head runat="server">
        <script src="jquery-2.1.4.js"></script>
    </head
    <script>


        jQuery.ajax = (function (_ajax) {

            var protocol = location.protocol,
                hostname = location.hostname,
                exRegex = RegExp(protocol + '//' + hostname),
                YQL = 'http' + (/^https/.test(protocol) ? 's' : '') + '://query.yahooapis.com/v1/public/yql?callback=?',
                query = 'select * from html where url="{URL}" and xpath="*"';


            function isExternal(url) {
                return !exRegex.test(url) && /:\/\//.test(url);
            }

            return function (o) {

                var url = o.url;

                if (/get/i.test(o.type) && !/json/i.test(o.dataType) && isExternal(url)) {

                    // Manipulate options so that JSONP-x request is made to YQL

                    o.url = YQL;
                    o.dataType = 'json';

                    o.data = {
                        q: query.replace(
                            '{URL}',
                            url + (o.data ?
                                (/\?/.test(url) ? '&' : '?') + jQuery.param(o.data)
                            : '')
                        ),
                        format: 'xml'
                    };


                    if (!o.success && o.complete) {
                        o.success = o.complete;
                        delete o.complete;
                    }

                    o.success = (function (_success) {
                        return function (data) {

                            if (_success) {

                                _success.call(this, {
                                    responseText: (data.results[0] || '')
                                   .replace(/<script[^>]+?\/>|<script(.|\s)*?\/script>/gi, '')
                                }, 'success');
                            }

                        };
                    })(o.success);

                }

                return _ajax.apply(this, arguments);

            };

        })(jQuery.ajax);

        $.ajax({
            url: 'http://www.mtbc.com/about-us/press-room/',
            type: 'GET',
            success: function (res) {
                console.log(res);
                $('#content').html(res.responseText);
            }
        });

    </script>

Html Markup

<div id="content">
    Searching....
    </div>

解决方案

Try using:

xpath='//div[contains(@class,"row device-margin-b50")]'

This way you should only get div with class you wanted.

这篇关于从拉跨域HTML元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！