本文介绍了Math.Pow给人"无法隐式转换类型'双'到'浮动'"错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在这个节目,我想创建一个简单的计算器。不过,我似乎无法找到一个方法达到 Math.Pow
线时要克服上述错误。
命名空间BinaryCalc
{
类二进制
{
公共静态无效的主要()
{ INT加法,减法;
浮分裂,增殖,电力,开方; INT X;
诠释Ÿ;
X = 10;
Y = 7; //Console.WriteLine(\"Please输入对于x)的数;
//串线=到Console.ReadLine();
// INT X = int.Parse(线); //Console.WriteLine(\"Please输入y)的一个号码;
//字符串LINE2 =到Console.ReadLine();
// INT Y = int.Parse(2号线);
此外=(INT)X +(INT)Y;
减法=(INT)x - (INT)Y;
师=(浮点)X /(浮动)Y;
乘法=(浮点)X *(浮动)Y; 功率= Math.Pow(X,2);
开方=的Math.sqrt(x)的;
Console.WriteLine(加法结果以{0},补充);
Console.WriteLine(减法,在{0}减法的结果);
Console.WriteLine(师的结果{0},除);
Console.WriteLine(乘法在{0}相乘的结果);
Console.WriteLine({0}平方在{0}结果,X,功率);
Console.WriteLine({0}的平方根:{0},X,开方); }
}
}
解决方案
Math.Pow使用双击
参数。正如错误说,没有的隐的从转换双
到浮动
,所以转换结果的明确的浮动:
功率=(浮点)Math.Pow(X,2);
修改结果
修正后的转换顺序
In this program I am trying to create a simple calculator. However, I can't seem to find a way to overcome the aforementioned error when reaching the Math.Pow
line.
namespace BinaryCalc
{
class Binary
{
public static void Main()
{
int addition,subtraction;
float division, multiplication, power, sqrt;
int x;
int y;
x = 10;
y = 7;
//Console.WriteLine("Please enter a number for x");
//string line = Console.ReadLine();
//int x = int.Parse(line);
//Console.WriteLine("Please enter a number for y");
//string line2 = Console.ReadLine();
//int y = int.Parse(line2);
addition = (int)x + (int)y;
subtraction = (int)x - (int)y;
division = (float)x / (float)y;
multiplication = (float)x * (float)y;
power = Math.Pow(x,2);
sqrt = Math.Sqrt(x);
Console.WriteLine(" Addition results in {0}", addition);
Console.WriteLine(" Subtraction results in {0}", subtraction);
Console.WriteLine(" Division results in {0}", division);
Console.WriteLine(" Multiplication results in {0}", multiplication);
Console.WriteLine(" {0} squared results in {0}",x, power);
Console.WriteLine(" Square root of {0} is: {0}", x, sqrt);
}
}
}
解决方案
Math.Pow uses a double
argument. As the error says, there is no implicit conversion from double
to float
, so convert the result explicitly to float:
power = (float)Math.Pow(x, 2);
EDIT
corrected the conversion order
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