比较2 phpinfo设置

问题描述

我想比较一下我在2台不同服务器上的设置.两者都是共享主机，因此我认为我没有足够的访问权限，只能通过phpinfo进行编程.因此，既然我有2个输出，我想比较它们而不需要手动检查它们.有自动化的方法吗?

I'd like to compare the settings I have on 2 different servers. Both are shared hosting so I don't think I have enough access to do it any other way but programmatically with phpinfo. So now that I have the 2 outputs, I'd like to compare them without examining them manually. Is there an automated way for this?

此外，作为附带说明，我认为是phpinfo是php.ini的输出.这是正确的吗?

Also, as a side but related note, I think phpinfo is the output of php.ini. Is this correct?

推荐答案

来自PHP手册，位于phpinfo():

From the PHP Manual on phpinfo():

phpinfo()的作用不只是打印出php.ini设置.

phpinfo() does more than just printing out php.ini settings.

如果要手动处理php.ini设置，则可能要签出 ini_get_all() 而不是phpinfo().这将返回所有配置值的数组.

If you want to process php.ini settings manually, you might want to check out ini_get_all() instead of phpinfo(). This returns an array of all configuration values.

您可以将ini_get_all()的输出从服务器A传输到服务器B(例如，通过使用 var_export() 创建PHP代码以创建数组，或者 serialize() )，然后使用 array_diff_assoc() 比较设置.

You could transfer the output of ini_get_all() from server A to server B (for example by using var_export() to create PHP code to create the array, or serialize()), then use array_diff_assoc() to compare the settings.

export.php :(服务器A)

<?php echo serialize(ini_get_all()); ?>

compare.php :(服务器B)

<?php
function ini_flatten($config) {
    $flat = array();
    foreach ($config as $key => $info) {
        $flat[$key] = $info['local_value'];
    }
    return $flat;
}

function ini_diff($config1, $config2) {
    return array_diff_assoc(ini_flatten($config1), ini_flatten($config2));
}

$config1 = ini_get_all();

$export_script = 'http://server-a.example.com/export.php';
$config2 = unserialize(file_get_contents($export_script));

$diff = ini_diff($config1, $config2);
?>
<pre><?php print_r($diff) ?></pre>

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