本文介绍了如何通过在移动Web浏览器中使用输入[type ='file']在捕获照片后在画布中绘制具有正确方向的照片?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在移动中创建一个简单的网络应用程序,允许访问者使用html5 input [type = file]元素捕获照片。然后我会将其显示在网络上进行预览,然后访问者可以选择将照片上传到我的服务器用于其他目的(即:上传到FB)

I am making a simple web app in mobile which allow visitor to capture photo by using html5 input[type=file] element. Then I will display it on the web for preview, and then visitor can choose to upload the photo to my server for other purpose(ie: upload to FB)

当我使用我的iPhone拍照并保持垂直照片的方向问题。照片是在标签中正确的方向。
然而,当我尝试使用drawImage()方法绘制到画布上时,它被绘制90度旋转。

I find a problem on the orientation of photo when I take photo using my iPhone and hold vertically.The photo is in a correct orientation in tag.However, when I try to draw it into canvas by using drawImage() method, it is drawn 90 degree rotated.

我试图拍照4方向,只有一个可以在画布上绘制正确的图像,其他的旋转或甚至上下颠倒。

I have tried to take photo in 4 orientations, only one of them can draw a correct image in canvas, others are rotated or even flipped upside down.

好吧,我很困惑得到正确的方向来解决这个问题...
感谢您的帮助...

Well, I am confused to get the correct orientation to fix this problem...Thanks for helping...

这里是我的代码,大多数是从MDN复制的

here is my code, mostly copy from MDN

<div class="container">
            <h1>Camera API</h1>

            <section class="main-content">
                <p>A demo of the Camera API, currently implemented in Firefox and Google Chrome on Android. Choose to take a picture with your device's camera and a preview will be shown through createObjectURL or a FileReader object (choosing local files supported too).</p>

                <p>
                    <form method="post" enctype="multipart/form-data" action="index.php">
                        <input type="file" id="take-picture" name="image" accept="image/*">
                        <input type="hidden" name="action" value="submit">
                        <input type="submit" >
                    </form>
                </p>

                <h2>Preview:</h2>
                <div style="width:100%;max-width:320px;">
                    <img src="about:blank" alt="" id="show-picture" width="100%">
                </div>

                <p id="error"></p>
                <canvas id="c" width="640" height="480"></canvas>
            </section>

        </div>


        <script>
            (function () {
                var takePicture = document.querySelector("#take-picture"),
                    showPicture = document.querySelector("#show-picture");

                if (takePicture && showPicture) {
                    // Set events
                    takePicture.onchange = function (event) {
                        showPicture.onload = function(){
                            var canvas = document.querySelector("#c");
                            var ctx = canvas.getContext("2d");
                            ctx.drawImage(showPicture,0,0,showPicture.width,showPicture.height);
                        }
                        // Get a reference to the taken picture or chosen file
                        var files = event.target.files,
                            file;
                        if (files && files.length > 0) {
                            file = files[0];
                            try {
                                // Get window.URL object
                                var URL = window.URL || window.webkitURL;

                                // Create ObjectURL
                                var imgURL = URL.createObjectURL(file);

                                // Set img src to ObjectURL
                                showPicture.src = imgURL;

                                // Revoke ObjectURL
                                URL.revokeObjectURL(imgURL);
                            }
                            catch (e) {
                                try {
                                    // Fallback if createObjectURL is not supported
                                    var fileReader = new FileReader();
                                    fileReader.onload = function (event) {
                                        showPicture.src = event.target.result;

                                    };
                                    fileReader.readAsDataURL(file);
                                }
                                catch (e) {
                                    // Display error message
                                    var error = document.querySelector("#error");
                                    if (error) {
                                        error.innerHTML = "Neither createObjectURL or FileReader are supported";
                                    }
                                }
                            }
                        }
                    };
                }
            })();
        </script>


推荐答案

您需要读取exif数据并检查if exif.Orientation是以下之一:

You'll need to read the exif data and check if exif.Orientation is one of the following:

fileReader.onloadend = function() {

    var exif = EXIF.readFromBinaryFile(new BinaryFile(this.result));

    switch(exif.Orientation){

       case 8:
           ctx.rotate(90*Math.PI/180);
           break;
       case 3:
           ctx.rotate(180*Math.PI/180);
           break;
       case 6:
           ctx.rotate(-90*Math.PI/180);
           break;


    }
};

这篇关于如何通过在移动Web浏览器中使用输入[type ='file']在捕获照片后在画布中绘制具有正确方向的照片?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-29 12:36