问题描述
我有一个工厂，返回一个智能指针。无论我使用什么智能指针，我都无法获得Google Mock来模拟工厂方法。
I have a factory that returns a smart pointer. Regardless of what smart pointer I use, I can't get Google Mock to mock the factory method.
mock对象是纯抽象接口的实现，其中所有方法是虚拟的。我有一个原型：
The mock object is the implementation of a pure abstract interface where all methods are virtual. I have a prototype:
MOCK_METHOD0(Create, std::unique_ptr<IMyObjectThing>());
我得到：
"...gmock/gmock-spec-builders.h(1314): error C2248: 'std::unique_ptr<_Ty>::unique_ptr' : cannot access private member declared in class 'std::unique_ptr<_Ty>'"
定义智能指针指向的类型。
The type pointed to in the smart pointer is defined.
我得到它试图访问一个声明为私有的构造函数，但我不明白为什么。当这是一个std :: auto_ptr，错误说没有复制构造函数，这让我困惑。
And I get it's trying to access one of the constructors declared private, but I don't understand why. When this was an std::auto_ptr, the error said there was no copy constructor, which confuses me.
无论如何，有一种方法来模仿一个方法，智能指针？还是有更好的方式来建立一个工厂？是我唯一的决心返回一个原始指针（blech ...）？
Anyway, is there a way to Mock a method that returns a smart pointer? Or is there a better way to build a factory? Is my only resolve to return a raw pointer (blech...)?
我的环境是Visual Studio 2010 Ultimate和Windows 7.我没有使用CLI。 / p>
My environment is Visual Studio 2010 Ultimate and Windows 7. I'm not using CLI.
推荐答案
在大多数情况下，Google Mock需要可以复制模拟方法的参数和返回值。根据，unique_ptr不是可复制。您可以选择返回使用共享所有权的智能指针类之一（，linked_ptr等），因此是可复制的。或者你可以使用原始指针。因为所讨论的方法显然是构造对象的方法，所以我没有看到返回原始指针的固有问题。只要在每个调用站点将结果分配给一些共享指针，你就会很好。
Google Mock requires parameters and return values of mocked methods to be copyable, in most cases. Per boost's documentation, unique_ptr is not copyable. You have an option of returning one of the smart pointer classes that use shared ownership (shared_ptr, linked_ptr, etc.) and are thus copyable. Or you can use a raw pointer. Since the method in question is apparently the method constructing an object, I see no inherent problem with returning a raw pointer. As long as you assign the result to some shared pointer at every call site, you are going to be fine.
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