问题描述
好的,这个问题以前可能已经被问过了,但是在所有站点上,我都看过如何做到这一点"的解释,告诉我我做对了.
Okay, this question has probably been asked before, but on all sites I've looked the explanation on "how to do this" tells me I'm doing it completely right.
我知道我不是,因为我在本地主机tomcat上收到500个服务器错误,并且在我的服务器日志中收到以下错误:
I know I'm not, as I get a 500 server error on my localhost tomcat and I get the following error in my server logs:
javax.ws.rs.WebApplicationException: com.sun.jersey.api.MessageException: A message body writer for Java class com.myapp.domain.Location, and Java type class com.myapp.domain.Location, and MIME media type application/json was not found
因此,我要尝试的是使用Jersey(在Java中)开发RESTful Web服务.除我要返回JSON的事实外,其他一切都很好.我找不到与这些人不同的工作
So, what I'm trying to do is to develop a RESTful web service with Jersey (in Java). Everything is going fine, except for the fact that I want to return JSON. I can't find what I'm doing different from these people:
- 如何在Jersey Rest中以JSON格式发送响应
- http://www.jasonwhaley.com/blog/2011/01/18/multiple-content-types-in-jax-rs/
- https ://github.com/jasonray/jersey-starterkit/wiki/Serializing-a-POJO-to-xml-or-json-using-JAXB
- https://github.com/jasonray/jersey-starterkit/wiki/Serializing-a-POJO-to-json-using-built-in-jersey-support
- http://www.vogella.com/tutorials/REST/article.html
- How to send response as JSON in Jersey Rest
- http://www.jasonwhaley.com/blog/2011/01/18/multiple-content-types-in-jax-rs/
- https://github.com/jasonray/jersey-starterkit/wiki/Serializing-a-POJO-to-xml-or-json-using-JAXB
- https://github.com/jasonray/jersey-starterkit/wiki/Serializing-a-POJO-to-json-using-built-in-jersey-support
- http://www.vogella.com/tutorials/REST/article.html
我的POJO(位置)如下:
My POJO (Location) looks like this:
package com.myapp.domain;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement()
public class Location {
private int id;
private double longtitude;
private double latitude;
public Location() {
new Location(-1, -1, -1);
}
public Location(double longtitude, double latitude) {
new Location(-1, longtitude, latitude);
}
public Location(int id, double longtitude, double latitude) {
this.id = id;
this.longtitude = longtitude;
this.latitude = latitude;
}
public void setID(int id) {
this.id = id;
}
public void setLongtitude(double longtitude) {
this.longtitude = longtitude;
}
public void setLatitude(double latitude) {
this.latitude = latitude;
}
public int getID() {
return this.id;
}
public double getLongtitude() {
return this.longtitude;
}
public double getLatitude() {
return this.latitude;
}
}
我的资源如下:
package com.myapp.MyAPP;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import com.myapp.domain.Location;
@Path("Locations")
public class LocationInfo {
@GET
@Path("/get/{id}")
@Produces(MediaType.APPLICATION_JSON)
public Location getLocation(@PathParam("id") int id) {
Location loc = new Location(3, 4.007391, 51.00237);
return loc;
}
}
这是我的web.xml:
And this is my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID"
version="2.5">
<display-name>MyAPP</display-name>
<servlet>
<servlet-name>MyAPP REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.myapp.MyAPP</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>MyAPP REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
我已经包含了以下库:asm-3.1.jar
,jersey-client-1.17.1.jar
,jersey-core-1.17.1.jar
,jersey-json-1.17.1.jar
,jersey-server-1.17.1.jar
,jersey-servlet-1.17.jar
,jsr11-api-1.1.1.jar
I've got these libraries included: asm-3.1.jar
, jersey-client-1.17.1.jar
, jersey-core-1.17.1.jar
, jersey-json-1.17.1.jar
, jersey-server-1.17.1.jar
, jersey-servlet-1.17.jar
, jsr11-api-1.1.1.jar
看到我没看到的东西的人会喝啤酒.或至少是我永恒的感激之情,因为我已经看了太久了,但仍然看不到.
The one who sees what I'm not seeing gets a beer. Or at least my eternal gratitude, cause I've been looking at this for way too long and I still can't see it.
推荐答案
好的,所以我发现orid有正确的答案:我只需要添加一些额外的库!
Okay, so I turned out orid had the right answer: I simply needed to add some extra libraries!
我可能忽略了它,或者大多数教程可能都假设您立即添加了使用jersey下载的所有库...
I probably overlooked it or most tutorials probably suppose you add all the libraries you download with jersey straight away...
所以这解决了问题:添加
So this fixed the problem: adding
-
jackson-core-asl-1.9.2.jar
-
jackson-jaxrs-1.9.2.jar
-
jackson-mapper-asl-1.9.2.jar
-
jackson-xc-1.9.2.jar
jackson-core-asl-1.9.2.jar
jackson-jaxrs-1.9.2.jar
jackson-mapper-asl-1.9.2.jar
jackson-xc-1.9.2.jar
再次感谢orid,您刚刚保存了我的周末.
Thanks again to orid, you just saved my weekend.
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