本文介绍了如何使用mongo-driver在Go中执行聚合的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个包含3个字段的MongoDB集合:
I have a MongoDB collection with 3 fields:
_id: ObjectId
field1: Number
field2: Number
我正在执行此聚合以获取不同的" field1/field2行,并对结果进行总计.可以在客户端(Robo3t)中正常运行:
I am doing this aggregation to get "distinct" field1/field2 rows and doing a total count of the results. This works OK in the client (Robo3t):
db.mycollection.aggregate([
{
$group: {
_id: { field1: "$field1", field2: "$field2" },
}
},
{
$group: {
_id: null, count: { $sum: 1 }
}
}
])
结果:
{
"_id" : null,
"count" : 57.0
}
如何使用 mongo-driver在Go中进行聚合?
How could I do this aggregation in Go using mongo-driver?
有此方法来执行聚合但是文档对我来说还不清楚.我知道我应该进行某种bson查询,但是我不知道从哪里开始.
There is this method to perform aggregations but the documentation is not clear to me. I understand that I should do some kind of bson query but I don't know where to start.
推荐答案
group :=[]bson.M{bson.M{
"$group": bson.M{
"_id":bson.M{
"field1": "$field1",
"field2": "$field2"
}
}
},
bson.M {
"$group": bson.M{
"_id":nil,
"count": bson.M{
"$sum":1
}
}
}
}
cursor, err := coll.Aggregate(context.Background(), mongo.Pipeline{group})
if err != nil {
log.Fatal(err)
}
尝试上述解决方案,它将起作用.
Try the above solution, It will works.
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