弹性搜索查询从regexp输入参数中查找列表中值的完全匹配

问题描述

我的数据如下:

  {
    "name": "name1",
    "name_gr": ["gr1","gr2"]
  },
  {
    "name": "name2",
    "name_gr": ["gr1","gr2"]
  },
  {
    "name": "name3",
    "name_gr": ["gr2","gr3"]
  },
  {
    "name": "name4",
    "name_gr": ["gr1","gr2","gr3","gr4"]
  },
  {
    "name": "name4",
    "name_gr": ["gr4","gr5"]
  }

现在，我正在尝试通过 elasticsearch_dsl python模块通过从其中导入 Q 来编写弹性搜索查询.

Now, i am trying to write elastic search query using elasticsearch_dsl python module by importing Q from it.

我的输入查询将是"name_gr" 上的一些 regex .例如:"name_gr":"gr [12]" .因此，在这种情况下，我希望所有在"name_gr"列表中同时具有"gr1"和"gr2"的名称.

My input query will be some regex on "name_gr". For eg: "name_gr": "gr[12]".So, in this case I want all the names which has both "gr1" and "gr2" in their list of "name_gr".

因此，->

示例1:"name_gr":"gr [12]" 将是:

  {
    "name": "name1",
    "name_gr": ["gr1","gr2"]
  },
  {
    "name": "name2",
    "name_gr": ["gr1","gr2"]
  },
  {
    "name": "name4",
    "name_gr": ["gr1","gr2","gr3","gr4"]
  }

因为gr1，gr2都出现在name1，name2和name4中.

because, gr1 and gr2 both are present in name1, name2 and name4.

示例2:"name_gr":"gr.*" 为:

  {
    "name": "name4",
    "name_gr": ["gr1","gr2","gr3","gr4"]
  }

因为所有的gr(gr1，gr2，gr3，gr4)都只出现在name4中.

because, all the gr's (gr1,gr2,gr3,gr4) are present in name4 only.

我尝试如下编写查询:

must = [{'match':{'regexp': {'name_gr': 'gr[12]'}}}]
result = Q('bool', must = must)

但是它也给出了name3，这是无效的，因为gr1和gr2都不存在.请帮忙.从现在开始，我一直陷入困境.

But it gives name3 also in result, which is invalid as both gr1 and gr2 are not present in it. Please help. I am stuck in this from few days now.

谢谢.

推荐答案

在您的示例中，您想使用 regexp 来使用 match 查询.为此，只需使用:

You are using a match query in your example where you want to be using regexp instead. To do this just use:

s = Search().query('regexp', name_gr='gr[12]')
s.execute()

希望这会有所帮助！

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