双指针中的内存泄漏

问题描述

你好
我正在使用类似
的结构

Hello
I am using a structure like

struct abc
{
	int		x;		
	int		y;
};

struct abcArray
{
	int iCount;
	abc **test;
};

进一步使用like(内存分配):

Further Use this like(memory allocation):

abcArray xyz;
xyz.test = new abc*;
for(int i = 0 ; i < 10 ; i++)
   xyz.test[i] = new xyz;

对于重新分配:

For deallocation:

for(int i = 0 ; i < 10 ; i++)
{
   delete[] xyz.test[i];
   xyz.test[i] = NULL;
}

当我检查内存泄漏时，它在
上显示泄漏

When I check for memory leaks,it says leak at

xyz.test = new abc*;

有人可以建议我如何分配以避免这种泄漏吗?

Can anybody suggest me how I should deallocate to avoid this leak?

推荐答案

abcArray xyz;
xyz.test = new abc*;
for(int i = 0 ; i < 10 ; i++)
   xyz.test[i] = new xyz;

您已经为单个abc结构分配了一个指针，然后继续访问以下不属于您的9个单元格.您应该像这样分配:

You have allocated a pointer to a single abc structure and then proceeded to access the following 9 cells which do not belong to you. You should allocate like:

xyz.test = new abc*[10];

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