问题描述
我正在尝试确定在执行以下操作后应将各种标志设置为(进位，符号，零，溢出):
I'm trying to determine what various flags should be set to (carry, sign, zero, overflow) after the following operation:
mov ax, 7ff0h; ax register is now 7ff0h
add al, 10h;
我对程序集如何处理感到困惑.由于我们仅添加了包含 f0h 的寄存器的al部分，因此 f0h + 10h 给出了 100h .这会设置溢出标志吗?进位标志?两者都不?我认为会设置溢出标志，但是，我想到的另一种可能性是程序检测到此情况并自动将ah寄存器从 7fh 更改为 80h ，从而完整的 ax 寄存器 8000h .从理论上讲，这不会设置进位标志，而是设置符号标志和溢出标志，因为我们的总数 8000h 现在为负.谁能解释这是怎么处理的?
I'm confused as to how assembly handles this. since we are adding to just the al portion of the register which contains f0h, f0h + 10h gives 100h. Does this set the overflow flag? The carry flag? Neither? I would think the overflow flag would be set, however, another possibility running through my mind is that the program detects this and automatically alters the ah register from 7fh to 80h, making the full ax register 8000h. This would in theory not set the carry flag, but would instead set the sign flag and overflow flag because our overall number 8000h is now negative. could anyone explain how this is handled?
谢谢.
推荐答案
我在使用debug命令(x86 Windows附带)方面有点过:
I have played a bit with the debug command (shipped with x86 Windows):
-a 100
1A2F:0100 mov ax, 7ff0
1A2F:0103 add al, 10
1A2F:0105
-t =100 2
AX=7FF0 BX=0000 CX=0000 DX=0000 SP=FFEE BP=0000 SI=0000 DI=0000
DS=1A2F ES=1A2F SS=1A2F CS=1A2F IP=0103 NV UP EI PL NZ NA PO NC
1A2F:0103 0410 ADD AL,10
AX=7F00 BX=0000 CX=0000 DX=0000 SP=FFEE BP=0000 SI=0000 DI=0000
DS=1A2F ES=1A2F SS=1A2F CS=1A2F IP=0105 NV UP EI PL ZR NA PE CY
1A2F:0105 0000 ADD [BX+SI],AL DS:0000=CD
-
NV [无溢出]PL(正)CY [Carry]
NV [No Overflow]PL (positive)CY [Carry]
这篇关于汇编语言-标志设置让我头疼的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！