本文介绍了Python:如何在列表中找到重复项,并通过重新命名添加渐进字符来更新这些重复项的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这样的项目列表:
['T1','T2','T2','T2' 'T2','T3','T3']
我需要确保重复的名称是以这样的方式添加的渐进字母:
['T1','T2A','T2B','T2C','T2D','T3A','T3B' ]
,但只有同一项目有超过1次出现。
任何想法?
解决方案
from collections import Counter
from string import ascii_uppercase as letters
def gen(L):
c = Counter(L)
for elt,count in c.items():
if count == 1:
yield elt
else:
for letter in letters [:count]:
yield elt + letter
现在:
>>&g吨; L = ['T1','T2','T2','T2','T2','T3','T3']
>>> list(gen(L))
['T2A','T2B','T2C','T2D','T3A','T3B','T1']
I have a list of items like this:
['T1','T2','T2','T2','T2','T3','T3' ]
I need to make sure that duplicates are renamed with a progressive letter added like this:
['T1','T2A','T2B','T2C','T2D','T3A','T3B']
but only if there is more than 1 occurrence of the same item.
Also, is it possible to do so without generating a new list?
Any ideas?
解决方案
from collections import Counter
from string import ascii_uppercase as letters
def gen(L):
c = Counter(L)
for elt, count in c.items():
if count == 1:
yield elt
else:
for letter in letters[:count]:
yield elt + letter
Now:
>>> L = ['T1','T2','T2','T2','T2','T3','T3']
>>> list(gen(L))
['T2A', 'T2B', 'T2C', 'T2D', 'T3A', 'T3B', 'T1']
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