本文介绍了拆分字符串时如何避免删除尾随空项目?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在做:
"b::::c:::".split(':')
结果:
["b", "", "", "", "c", "", ""] # expect
["b", "", "", "", "c"] # actual
这里有什么问题?我怎样才能得到我所期望的.
What is the problem here? how can i get what i expected.
推荐答案
.split(pattern=$;, [limit]) 有一个 limit 参数.如果省略 limit，则抑制尾随空字段.您需要提供一个负 limit
There's a limit parameter to .split(pattern=$;, [limit]). If limit is omitted, trailing null fields are suppressed. You need to provide a negative limit
"b::::c:::".split(':', -1)
但请记住，这将在数组末尾返回三个 "" 值.
but bear in mind that this will return three "" values at the end of the array.
result: ["b", "", "", "", "c", "", "", ""]
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