问题描述
如何将指数分布覆盖在时间间隔的直方图上?直方图看起来像是指数分布.当我尝试以类似于叠加法线的方式创建直方图时，得到以下信息:
How can i overlay an exponential distribution on a histogram of time intervals? The histogram looks like an exponential distribution.When I try to create the histogram in a similar way to superimposing a normal curve I get the following:
Error in xy.coords(x, y) : 'x' and 'y' lengths differ
我可以自己创建直方图，直方图的x轴从0到70.我可以自己创建指数分布曲线，但x轴从0到1.
I can create the histogram on its own which has an x axis from 0 to 70. And I can create an exponential distribution curve on its own but its x axis goes from 0 to 1.
我正在使用hist(t)，其中t是直方图以秒为单位的时间列表和curve(dexp(x,rate=0.09))用于指数分布.
I am using hist(t) where t is a list of times in seconds for the histogramand curve(dexp(x,rate=0.09)) for the exponential distribution.
推荐答案
请确保在hist中使用prob = TRUE，在curve
z <- rexp(300,rate = 0.09)
hist(z, prob = TRUE)
curve(dexp(x, rate = 0.09), col = 2, lty = 2, lwd = 2, add = TRUE)
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