本文介绍了查找大于CUDA中阈值的索引和值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个矩阵,我想找到大于阈值的索引和值,那么如何使用CUDA呢?还是将矩阵复制到内存中并让cpu完成工作的更好方法?
I have a matrix and I want to find the indices and values that larger than a threshold,so how to do it with CUDA? Or it's a better way to copy the matrix to memory and let cpu do the work?
推荐答案
您可以使用以下方法轻松实现,它为您提供了所需的基本构件。以下代码首先找到满足条件的索引(值>阈值
),然后提取相应的值。如果不需要索引,则可以一步一步完成所有操作。
You can implement this very easily using Thrust, which offers you the basic building blocks you need. The following code first finds the indices which fulfill the condition (value > threshold
) and then extracts the corresponding values. If you don't need the indices, you can do all this in one step.
#include <thrust/gather.h>
#include <thrust/iterator/counting_iterator.h>
#include <thrust/iterator/permutation_iterator.h>
#include <thrust/functional.h>
#include <thrust/copy.h>
#include <thrust/device_vector.h>
#include <iostream>
#include <thrust/sequence.h>
int main()
{
const int N = 100;
int threshold = 90;
thrust::device_vector<int> data(N);
// fill with demo data
thrust::sequence(data.begin(), data.end());
// find out the indices
thrust::device_vector<int> indices(N);
thrust::device_vector<int>::iterator end = thrust::copy_if(thrust::make_counting_iterator(0),
thrust::make_counting_iterator(N),
data.begin(),
indices.begin(),
thrust::placeholders::_1 > threshold);
int size = end-indices.begin();
indices.resize(size);
// fetch corresponding values
thrust::device_vector<int> values(size);
thrust::copy(thrust::make_permutation_iterator(data.begin(), indices.begin()),
thrust::make_permutation_iterator(data.end(), indices.end()),
values.begin());
std::cout << "indices: ";
thrust::copy(indices.begin(), indices.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << std::endl;
std::cout << "values: ";
thrust::copy(values.begin(), values.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << std::endl;
return 0;
}
此演示程序的输出为:
indices: 91 92 93 94 95 96 97 98 99
values: 91 92 93 94 95 96 97 98 99
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