"BEGIN块必须具有动作部分". awk脚本中的错误

问题描述

这是我的代码:

#!/bin/sh

filename=$(/usr/bin/find -name "INSTANCE-*.log")
echo "filename is " $filename

awk '
 BEGIN
 {   
   print "Processing file: " filename 
 }

 {
  if($0 ~ /Starting/) 
  { 
    print "The bill import has been Started on "$1 " " $2
  }

}'  $filename > report.txt

当我执行它时，出现以下错误:

When I execute it I get the following error:

我的BEGIN块具有print语句，因此它具有动作部分.我在这里想念什么?

My BEGIN block has a print statement so it has an action part. What am I missing here?

推荐答案

之所以会这样，是因为您的大括号位于下一行.

This happens because your opening curly brace is in the next line.

所以您需要做的是这样写BEGIN { ...:

So what you need to do is to write BEGIN { ... like this:

BEGIN {
print "Processing file: " filename 
}

---

还请注意，可以将主块重写为:

---

Note also that the main block can be rewritten to:

/Starting/ {print "The bill import has been Started on "$1 " " $2}

也就是说，if ()和$0是隐式的，因此可以跳过.

That is, if () and $0 are implicit so they can be skipped.

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