本文介绍了我如何...盒子在盒子里,因为我只有一个盒子,但内盒没有被填满的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

想法是取一个数字作为输入并打印一个盒子的模式



如果输入为2,则两个盒子要打印在另一个内部



最小的盒子大小为3 * 3,下一个大盒子将是5 * 5,下一个盒子将是7 * 7,依此类推/>


输入1,然后画一个尺寸为3 * 3的盒子



对于输入2,外盒将是5 * 5,内部将是3 * 3



对于输入3,外盒将是7 * 7,另外还有2个内盒



因此对于n,最外面的盒子将是n * 2 + 1大小,带有(n1)个内盒子



所有盒子将左上角对齐,如图所示



输入格式:



第一行输入包含一个数字N



输出格式:



打印N个嵌套的盒子



限制条件:



1. 0< N< 25



我的尝试:



Idea is to take a number as input and print a pattern of boxes

If input is 2, two boxes are to be printed ­ one inside the other

Smallest box will be of size 3*3, the next bigger box will be 5*5, the next one will be 7*7, so on and so forth

For input 1, then draw a box of dimensions 3*3

For input 2, outer box will be 5*5, inner will be 3*3

For input 3, outer box will be 7*7, with 2 more inner boxes

So for n, outermost box will be n*2 +1 in size, with (n­1) inner boxes

All boxes will be top left aligned as shown in the figure

Input Format:

First line of input contains a number N

Output Format:

Print N nested boxes

Constraints:

1. 0 < N < 25

What I have tried:

#include<stdio.h>
#include<conio.h>
int main()
{
    int j,i,n;
    scanf("%d",&n);
    for(j=0;j<n-2;j++)>
        printf("-");
    printf("\n");

    for(i=0;i<n;i++)>
    {
        printf("-");
        for(j=0;j<n-2;j++)>
            printf(" ");
        printf("-\n");
    }
    for(j=0;j<n;j++)>
        printf("-");
    printf("\n");
    //}
    return(0);
}

推荐答案

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***




*****
*****
** **
*****
*****




*******
*******
*******
*** ***
*******
*******
*******

而且很明显发生了什么:所有的行都是实心的,除了中间的一行,中间只有一个空白。

从那,它是非常简单:一个外部循环绘制每一行,两个内部循环绘制线的左半部分和右半部分,但决定在行的中间打印星形或空格。

试一试:它并不像你想象的那么难!

And it's pretty obvious what is happening: all the rows are solid, except the centre one which contains a single blank in the middle.
From that, it's pretty simple: One outer loop to draw each line, and two inner loops to draw the left and right halves of the line but a decision to print a star or a space in the middle of the line.
Try it: it isn't as difficult as you think!


+---+
|+-+|
|| ||
|+-+|
+---+



并推断您需要编程以再现相同的图纸。


and deduce what you need to program to reproduce the same drawing.


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06-18 18:37