什么是添加单在C做一个字符数组？

问题描述

我期待通过一些code为学习的目的。我通过code的这部分工作。

I'm looking through some code for learning purposes. I'm working through this portion of code.

// e.g. const unsigned char data={0x1,0x7C ... }
unsigned char buf[40];
memset(buf,0,40);
buf[0] = 0x52;
memcpy(buf+1, data, length); // What does buf+1 do in this situation?

在最后一行，其中的memcpy叫什么buf绝对不+ 1吗？ buf是一个字符数组，那么是什么+1办呢？

On the last line where memcpy is called what does buf+1 do? buf is a character array, so what does +1 do to it?

推荐答案

在C，每一个数组名是一个指针，所以这里的buf也意味着指针，指向的buf [0]。那么BUF + 1是指 BUF [1]的地址。

In C, every array name is a pointer, so buf here also means the pointer which point to buf[0].Then "buf+1" means "buf[1]"'s address.

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