问题描述
编码社区的智能成员比我多！我对所有人都有一个python问题...：）
more-intelligent-members-of-the-coding-community-than-I! I have a python question for you all... :)
我正在尝试优化一个python脚本，该脚本（除其他外）返回挂钟时间a子进程执行并终止。我想我已经接近了这样的事情。
I am trying to optimize a python script that is (among other things) returning the wall-clock time a subprocess took execute and terminate. I think I'm close with something like this.
startTime = time.time()
process = subprocess.Popen(['process', 'to', 'test'])
process.wait()
endTime = time.time()
wallTime = endTime - startTime
但是，我担心 subprocess.Popen（）在旧的和异国情调的平台上提高了我的结果。我的第一个倾向是通过运行一个简单的无害命令，以某种方式确定由 subprocess.Popen（）引起的开销。在Linux上如下所示。
However, I am concerned that the overhead in subprocess.Popen() is inflating my results on older and exotic platforms. My first inclination is to somehow time the overhead caused by subprocess.Popen() by running a simple innocuous command. Such as the following on linux.
startTime = time.time()
process = subprocess.Popen(['touch', '/tmp/foo'])
process.wait()
endTime = time.time()
overheadWallTime = endTime - startTime
或在Windows上执行以下操作。
Or the following on windows.
startTime = time.time()
process = subprocess.Popen(['type', 'NUL', '>', 'tmp'])
process.wait()
endTime = time.time()
overheadWallTime = endTime - startTime
所以，我该如何考虑在python中计时时 subprocess.Popen（）开销？
So, how should I account for subprocess.Popen() overhead when timing in python?
或者，什么是无开销的采样开销的方法？来自 subprocess.Popen（）？
Or, what is an innocuous way to sample the overhead from subprocess.Popen()?
或者，也许有些事情我还没有考虑？
Or, maybe there's something I haven't considered yet?
警告是解决方案必须合理地跨平台。
The caveat is that the solution must be reasonably cross-platform.
推荐答案
欢迎使用。
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