问题描述
这是我的输入内容
<array>
<string>extra1</string>
<string>extra2</string>
<string>Yellow
5</string>
注意:黄色"和"5"之间有空格和换行符
Note: there's a space and newline between "Yellow" and "5"
我正在将此管道用于sed:
I am piping this to sed:
| sed -n 's#.*<string>\(.*\)</string>#\1#p'
我得到了输出:
extra1
extra2
我知道,因为sed从每个输入行的末尾剥离换行符,所以换行符不匹配-因此要考虑结果.我已经阅读了有关从缓冲区添加下一行的文章,但是我无法弄清楚在模式匹配中需要使用什么来使它起作用.
I know that, because sed strips the newline from the end of each input line, the newline is not there to be matched - so that accounts for the result. I have read articles on adding the next line from the buffer, but I can't work out what I need to use in the pattern match to get this to work.
我想要的输出是:
extra1
extra2
Yellow 5
(如果有所作为,我使用的是Mac,因此我需要使用它-我认为-sed的FreeBSD变体.)
(In case it makes a difference, I am using a Mac, so I need this to work with - I think - the FreeBSD variant of sed.)
当然,如果其他工具更适合我想要实现的目标,我欢迎您提出建议!谢谢!
Of course, if another tool is better for what I want to achieve I am open to suggestions! Thanks!
推荐答案
加入这些行并将它们分开:
Join the lines and tear them apart:
tr -d "\n" < file| grep -o "<string>[^<]*</string>"|sed 's/<string>\(.*\)<\/string>/\1/'
这篇关于sed匹配换行符中的模式的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!