EmguCV中图像的傅立叶变换

问题描述

有人可以告诉我emgucv 2.3中是否存在用于查找图像的傅立叶变换的内置函数？

Can anyone tell me if there is an inbuilt function present in emgucv 2.3 for finding out fourier transform of images ?

预先感谢

推荐答案

从我的回答

您追求的功能是CvInvoke.cvDFT，它在技术上调用了opencv方法，但应该是您追求的功能

The function you are after is CvInvoke.cvDFT it is technically calling the opencv method but it should be what your after

下面是将cvDFT中的虚部和实部分开的代码：

Here is the code that splits the Imaginary and Real parts from cvDFT:

Image<Gray, float> image = new Image<Gray, float>(open.FileName);
IntPtr complexImage = CvInvoke.cvCreateImage(image.Size, Emgu.CV.CvEnum.IPL_DEPTH.IPL_DEPTH_32F, 2);

CvInvoke.cvSetZero(complexImage);  // Initialize all elements to Zero
CvInvoke.cvSetImageCOI(complexImage, 1);
CvInvoke.cvCopy(image, complexImage, IntPtr.Zero);
CvInvoke.cvSetImageCOI(complexImage, 0);

Matrix<float> dft = new Matrix<float>(image.Rows, image.Cols, 2);
CvInvoke.cvDFT(complexImage, dft, Emgu.CV.CvEnum.CV_DXT.CV_DXT_FORWARD, 0);

//The Real part of the Fourier Transform
Matrix<float> outReal = new Matrix<float>(image.Size);
//The imaginary part of the Fourier Transform
Matrix<float> outIm = new Matrix<float>(image.Size);
CvInvoke.cvSplit(dft, outReal, outIm, IntPtr.Zero, IntPtr.Zero);

//Show The Data
CvInvoke.cvShowImage("Real", outReal);
CvInvoke.cvShowImage("Imaginary ", outIm);

干杯，

Chris

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