将Math.sin(x)的结果转换为Java中度的结果

问题描述

我想将Math.sin(x)(其中x以弧度表示)转换为以x为度而不是弧度的结果.

I would like to convert the Math.sin(x), where x in radians to a result which will give me as x in degrees not radians.

我已经使用了普通的方法和度数和弧度之间的java内置方法进行转换，但是我传递给Math.sin()方法的任何参数都被视为弧度，从而使转换工作徒劳无功.

I have used the normal method and java built in method of conversion between degrees and radians, but any argument I pass to the Math.sin() method is being treated as radians, thereby causing my conversion to be a futile effort.

我希望给定sin输入的输出，就好像输入的度数不是Math.sin()方法那样以弧度表示.

I want the output of a sin Input to be given as if the input is treated in degrees not radians like the Math.sin() method does.

推荐答案

Java的Math库为您提供了在度和弧度之间转换的方法: toRadians 和 toDegrees :

Java's Math library gives you methods to convert between degrees and radians: toRadians and toDegrees:

public class examples
{
    public static void main(String[] args)
    {
         System.out.println( Math.toRadians( 180 ) ) ;
         System.out.println( Math.toDegrees( Math.PI ) ) ;
    }
}

如果输入的单位是度，则需要将输入到sin的数字转换为弧度:

If your input is in degrees, you need to convert the number going in to sin to radians:

double angle = 90 ;
double result  = Math.sin( Math.toRadians( angle ) ) ;
System.out.println( result ) ;

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