本文介绍了在未知索引处分割向量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在R中有一个向量,该向量至少包含50.000个实数.值从小到大排序,现在我需要将此向量拆分为不同的向量.当两个数字之间的差大于给定数字(例如两个)时,必须对向量进行拆分.
I have a vector in R which contains at least 50.000 reals.The values are ordered from small to large and now I need to split up this vector in different vectors. The vector has to be split up when the difference between two numbers is larger than a given number (say two).
示例
data <- c(1,1.1, 1.2, 4, 4.2, 8, 8.9, 9, 9.3);
# Then I need the following vectors:
x1 <- c(1, 1.1, 1.2);
x2 <- c(4, 4.2);
x3 <- c(8, 8.9, 9, 9.3);
困难在于我们不知道所需矢量的数量,也不知道正手每个矢量的长度.
The difficulty is that we don't know the number of needed vectors and don't know the length of each vector at forehand.
现在我有以下想法,但是这非常耗时,并且只能将向量分成两个新向量.
Now I have the following idea, however this is very time consuming and it is only able to split the vector into two new vectors.
j <- 2;
seqDemA1 <- seqDemandA[1];
while((seqDemandA[j-1] - seqDemandA[j] < 2) && (j < length(seqDemandA)+1)) {
seqDemA1 <- c(seqDemA1, seqDemandA[j]);
j <- j+1;
}
seqDemA2 <- seqDemandA[j];
j <- j+1;
while((seqDemandA[j-1] - seqDemandA[j] < 2) && (j < length(seqDemandA)+1)) {
seqDemA2 <- c(seqDemA2, seqDemandA[j]);
j <- j+1;
}
期待您的帮助!
推荐答案
尝试一下,
split(data, cumsum(c(0, diff(data)>=2)))
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