在C ++中将int设置为无穷大

问题描述

我有一个 int a ，需要等于infinity。这意味着如果

  int b = anyValue; 
  

a> b / p>

有没有C ++的特性可以使这成为可能？

解决方案

整数是有限的，所以可悲的是，你不能把它设置为一个真正的无穷。
然而，你可以将它设置为int的最大值，这意味着它将大于或等于任何其他int，例如：

  a> = b 
  

始终为真。

  #include< limits> 
 
 //你的代码在这里
 
 int a = std :: numeric_limits< int> :: max（）; 
 
 //走出去，过着幸福生活的生活
  

通常等于2,147,483,647

如果你真的需要一个真正的无限值，你必须使用双精度浮点数。

  float a = std :: numeric_limits< float> :: infinity（）; 
  

有关数字限制的其他说明，请参阅

快乐编码！

：正如WTP所提到的，如果绝对需要有一个无限的int，你必须为int编写一个包装类，并重载比较运算符，尽管这对大多数项目可能不是必需的。

I have an int a that needs to be equal to "infinity". This means that if

int b = anyValue;

a>b is always true.

Is there any feature of C++ that could make this possible?

解决方案

Integers are finite, so sadly you can't have set it to a true infinity.However you can set it to the max value of an int, this would mean that it would be greater or equal to any other int, ie:

a>=b

is always true.

You would do this by

#include <limits>

//your code here

int a = std::numeric_limits<int>::max();

//go off and lead a happy and productive life

This will normally be equal to 2,147,483,647

If you really need a true "infinite" value, you would have to use a double or a float. Then you can simply do this

float a = std::numeric_limits<float>::infinity();

Additional explanations of numeric limits can be found here

Happy Coding!

Note: As WTP mentioned, if it is absolutely necessary to have an int that is "infinite" you would have to write a wrapper class for an int and overload the comparison operators, though this is probably not necessary for most projects.

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