TD中的PIVOT实施

本文介绍了TD中的PIVOT实施的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我想透视我的数据，并且我知道我们在teradata 16中具有透视功能.我不确定如何使用它.我知道其他方法，例如max(case ...)，但是我的数据集很大，所以我不能使用它.

I want to pivot my data and i am aware that we have Pivot function in teradata 16.I am not sure how to use it. I am aware of other methods like max(case...) but my data set is large so i can't use that.

任何人都可以在这里告诉我如何使用数据透视:

Can anyone tell me how to use pivot here:

SERV_PROVIDER_ID    CALL_START_DT   cnt1    
50003                  4/15/2018    25,117  
50003                  4/16/2018    65,630  
50003                  4/17/2018    63,880  
50003                  4/18/2018    40,080

想要

SERV_PRIDER_ID  CALL_START_DT1 CNT1 CALL_START_DT2  CNT2 CALL_START_DT3 CNT3

我只需要4天的数据.

感谢您的帮助.

推荐答案

知道这四个日期时:

SELECT *
FROM mytab
PIVOT
 ( Sum(cnt1) 
   FOR CALL_START_DT
    IN (DATE'2018-04-15'
       ,DATE'2018-04-16'
       ,DATE'2018-04-17'
       ,DATE'2018-04-18'
       )
 ) AS dt;

但是您的预期结果看起来像是您希望动态地拥有那些日子:

But your expected result looks like you want those days dynamically:

WITH cte AS 
 (
   SELECT t.*,
      Row_Number()
      Over (PARTITION BY SERV_PROVIDER_ID
            ORDER BY CALL_START_DT) AS rn
   FROM mytab AS t
 )
SELECT * 
FROM cte
PIVOT
 ( Min(CALL_START_DT) AS CALL_START_DT,
   Sum(cnt1) AS Cnt
   FOR rn
    IN (1 
       ,2
       ,3
       ,4
       )
 ) AS dt;

这篇关于TD中的PIVOT实施的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！