本文介绍了C ++ 11字符串的分配要求的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 我听说C ++ 11需要 string s在连续内存中分配。我甚至认为我看到一个堆栈溢出问题，但我似乎找不到它。I had heard that C++11 was going to require strings to be allocated in contiguous memory. I even thought I saw a stack overflow question on it, but I can't seem to find it.我知道在实践中，gcc和Visual Studio做分配I know that in practice both gcc and Visual Studio do allocate strings contiguously, I'm just asking as to the standard's requirements.推荐答案 p> 2011年标准的第21.4.1.5节规定：Section 21.4.1.5 of the 2011 standard states: basic_string 对象应该连续存储。也就是说，对于任何 basic_string 对象 s ，标识 & （s.begin（）+ n）==& * s.begin（）+ n 将适用于 n 使得 0 。 The char-like objects in a basic_string object shall be stored contiguously. That is, for any basic_string object s, the identity &*(s.begin() + n) == &*s.begin() + n shall hold for all values of n such that 0 <= n < s.size().身份表达式的两部分是 以 begin（）迭代器前进 n ，然后取消引用并获取结果元素的地址。 使用 begin（）迭代器，的所得元素。将 n 添加到此指针。Take the begin() iterator, advance by n, then dereference and take the address of the resulting element.Take the begin() iterator, dereference and take the address of the resulting element. Add n to this pointer.由于两者都必须相同，这将强制执行连续存储;也就是说，迭代器不能在不违反这个要求的情况下移动任何不连续的存储。Since both are required to be identical, this enforces contiguous storage; that is, the iterator cannot move over any non-contiguous storage without violating this requirement. 这篇关于C ++ 11字符串的分配要求的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！
