不兼容的类型:可能从双精度整数转换为整数

问题描述

有帮助吗?我不知道为什么会收到此错误.我进入第39行:

Help? I don't know why I am getting this error. I am getting at in line 39:

term[1] = differentiate(Coeff[1], exponent[1]);

如何解决此问题?

完整的代码清单:

public class Calcprog {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int numTerms = 7;
        double[] Coeff = new double[6];
        double[] exponent = new double[6];
        String[] term = new String[6];

        System.out.println("Enter the number of terms in your polynomial:");
        numTerms = input.nextInt();

        while (numTerms > 6) {
            if (numTerms > 6) {
                System.out.println("Please limit the number of terms to six.");
                System.out.println("Enter the number of terms in your polynomial:");
                numTerms = input.nextInt();
            }
        }

        for (int i = 1; i < numTerms + 1; i++) {
            System.out.println("Please enter the coefficient of term #" + i + " in decimal form:");
            Coeff[i] = input.nextDouble();
            System.out.println("Please enter the exponent of term #" + i + " in decimal form:");
            exponent[i] = input.nextDouble();
        }
        term[1] = differentiate(Coeff[1], exponent[1]);
    }

    public String differentiate(int co, int exp) {
        double newco, newexp;
        String derivative;
        newexp = exp - 1;
        newco = co * exp;
        derivative = Double.toString(newco) + "x" + Double.toString(newexp);
        return derivative;
    }
}

推荐答案

您正试图将双参数传递给接受int的方法，该方法需要进行强制转换，这可能会导致信息丢失.

You are trying to pass double arguments to a method that accepts ints, which requires a casting that may result in loss of information.

您可以通过显式强制转换使其工作:

You can make it work by an explicit cast :

term[1] = differentiate((int)Coeff[1], (int)exponent[1]);

或者您可以将您的 differentiate 方法更改为接受双参数，这可能更有意义:

Or you can change your differentiate method to accept double arguments, which would probably make more sense :

public String differentiate(double co, double exp)

这篇关于不兼容的类型:可能从双精度整数转换为整数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！