如何在使用gdb调试递归函数时跳过一部分

问题描述

  void 
 quicksort（int * num，int p，int r ，int june）
 {
 int q，bbc，ccd; 
 if（p  {
 call ++; 
q = partition（num，p，r，june）; //<  - 我想在gdb session中跳过这个调用
 bbc = q  -  1  -  p + 1; //< - 并希望从这里一步一步地继续执行
 quicksort（num，p，q  -  1，bbc）; 
 ccd = r-q + 1; 
 quicksort（num，q + 1，r，ccd）; 
} 
} //因为它是一个递归函数，每次调用quicksort时，partition也会被执行我只想把调试的重点放在quicksort 
  我想跳过gdb显示分区的步骤，也就是我知道的函数分区是正确的，所以做什么分区，然后跳转到下一条指令
  bbc = q  -  1  -  p + 1; 
  
并且在我的调试会话中不显示有关分区的信息。 
所以我怎样才能跳过这部分并继续调试quicksort。
解决方案
我想你正在寻找一个 step over 。
在GDB中，通过发出 next 命令来完成此操作。 
在gdb中运行 q = partition（num，p，r，june）; 行时，输入 next  
 
你可以在这个。 
Here is a function in my program 
void
quicksort (int *num, int p, int r, int june)
{
  int q, bbc, ccd;
  if (p < r)
    {
      call++;
      q = partition (num, p, r, june);//<--I want to skip this call in gdb session
      bbc = q - 1 - p + 1;//<-- and want to continue execution step by step from here
      quicksort (num, p, q - 1, bbc);
           ccd=r-q+1;
      quicksort (num, q + 1, r, ccd);
    }
} //since it is a recursive function each time quicksort is called partition is also executed I want to focus my debugging only to quicksort
If you notice it calls another function  partition in between.While running in a gdb sessionI want to skip the gdb showing me steps of parition i.e. I know function partition is correct so do what partition does and then jump to next instruction 
     bbc = q - 1 - p + 1;
and in my debugging session do not show info about partition.So how can I skip that part and continue debugging quicksort.
 解决方案 
I think you are looking for a step over.
In GDB, you do this by issuing the next command.When you are running the q = partition (num, p, r, june); line in gdb, type next and it will just execute the partition function without going into its code in detail.
You can find detailed information about stepping in gdb in this reference.
                        
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