wsdl生成的Web Service客户端无法与已部署的Web Service一起使用

问题描述

我已经使用axis2 java2wsdl实用工具从Java类中生成了WSDL，如下所示:

I have generated a WSDL from a java class using axis2 java2wsdl utility as follows;

java2wsdl -o C:\temp -cn com.temenos.webservices.customer.CustomerServiceWS

然后，我已在axis2的Application Server(例如jBoss)中部署了相同的Web服务，并且可以在http://127.0.0.1:8080/axis2/services/CustomerServiceWS?wsdl上浏览wsdl并在上调用方法通过标准客户端(如SoapUI等)提供此服务.

Then I have deployed the same web service within an Application Server (say jBoss) in axis2 and I can browse the wsdl on http:// 127.0.0.1:8080/axis2/services/CustomerServiceWS?wsdl and call the methods on this service via standard client like SoapUI etc.

现在的问题是，当我使用标准Java工具' wsimport '通过将WSDL位置提供为 C:\ temp (从java2wsdl实用程序生成WSDL)生成客户端时， )，则我的客户端无法与Deployed Web Service通信.我正在使用以下代码访问Web服务；

The problem is now that when I generated a client using standard java tooling 'wsimport' by providing a WSDL location as C:\temp (Generated WSDL from java2wsdl utility), my client is unable to communicate with the Deployed Web Service. I am using following code to access the web service;

// Initialise WS
CustomerServiceWS service = null;
CustomerServiceWSPortType servicePort = null;
try {
URL wsdlLocation  = new URL("http://127.0.0.1:8080/axis2/services/CustomerServiceWS?wsdl");
QName serviceName = new QName("http://customer.webservices.temenos.com", "CustomerServiceWS");
service = new CustomerServiceWS(wsdlLocation, serviceName);
servicePort = service.getCustomerServiceWSHttpSoap12Endpoint();
} catch (MalformedURLException murle) {
murle.printStackTrace();
    return;
}

但是在创建(服务端口)端点时，出现以下错误；

But while creating an (service Port) Endpoint I am getting following error;

Exception in thread "main" javax.xml.ws.WebServiceException: An attempt was made to construct the ServiceDelegate object with an service name that is not valid: {http://customer.webservices.temenos.com}CustomerServiceWS.
    at org.apache.axis2.jaxws.ExceptionFactory.createWebServiceException(ExceptionFactory.java:173)
    at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:70)
    at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:118)
    at org.apache.axis2.jaxws.spi.ServiceDelegate.<init>(ServiceDelegate.java:218)
    at org.apache.axis2.jaxws.spi.Provider.createServiceDelegate(Provider.java:59)
    at javax.xml.ws.Service.<init>(Service.java:56)
    at com.temenos.webservices.customer.CustomerServiceWS.<init>(CustomerServiceWS.java:42)
    at com.temenos.services.customer.client.Client.testGetLanguage(Client.java:32)
    at com.temenos.services.customer.client.Client.main(Client.java:21)

我尝试了很多事情，但是似乎什么都不喜欢.我有什么想念的吗?

I have tried many things but it does not seems to like anything. Am I missing anything?

谢谢

-

Junejo

推荐答案

查看WSDL文件的描述，并检查targetNamespace以获取QName()中提供的URL.还要导入必要的程序包.

See the description of WSDL file and check the targetNamespace for the url to be given in QName(). Also import necessary packages.

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