本文介绍了函数声明后删除的含义的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class my_class
{
...
my_class(my_class const &) = delete;
...
};
= delete
?
是否有任何其他修饰符( = 0
和 = delete
)?
Are there any other "modifiers" (other than = 0
and = delete
)?
推荐答案
删除函数:
class X {
// ...
X& operator=(const X&) = delete; // Disallow copying
X(const X&) = delete;
};
[...]
删除机制可用于任何功能。例如,我们
可以消除不想要的转换,例如:
The "delete" mechanism can be used for any function. For example, we can eliminate an undesired conversion like this:
struct Z {
// ...
Z(long long); // can initialize with an long long
Z(long) = delete; // but not anything less
};
这篇关于函数声明后删除的含义的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!