使用Docker compose传递Dockerfile的参数

问题描述

我正在尝试在构建阶段对我的dockerfile进行参数化，并在Docker-compose中使用参数。例如，在Docker compose中，我定义了一个名为bpp的服务，如下所示：

I'm trying to use parametrize my dockerfiles on build phase and use arguments in Docker-compose. For example in Docker compose I have defined one service called bpp as following:

bpp:
  build:
    context: .
    dockerfile: Dockerfile.bpp
    args:
      gp : 8080
  image: serv/bpp
  restart: always
  depends_on:
    - data
  links:
    - data

我正在尝试传递名为gp的参数到Dockerfile.bpp，在启动Python应用程序时使用参数，公开端口等。
例如，在dockerfile.bpp中，尝试公开端口gp如下：

I'm trying to pass argument named gp to Dockerfile.bpp, where I'm using argument when starting a Python application, exposing a port etc.For example in dockerfile.bpp in trying to expose port gp as following:

EXPOSE gp

但是，在构建时命令 docker-compose build 的docker文件我收到以下错误：
错误：服务'bpp'生成失败：无效的containerPort：gp

However, when building docker file by command docker-compose build I get following error:ERROR: Service 'bpp' failed to build: Invalid containerPort: gp

似乎参数gp在dockerfile中不可见。

It seems that argument gp is not visible in dockerfile. Any suggestions?

推荐答案

您需要将 ARG gp 添加到Dockerfile中。

You need to add ARG gp to your Dockerfile.

...
ARG gp

EXPOSE $gp
...

值得一提的是这不会为了在通过compose运行端口时公开端口，您需要为此在docker-compose.yml中添加 ports 指令。

Worth mentioning that this isn't going to expose the port when you're running it via compose though, you would need to add a ports instruction to your docker-compose.yml for that.

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