问题描述
Scala 有各种各样的不可变序列，如 List、Vector 等.我很惊讶地发现没有由简单数组支持的不可变索引序列的实现(Vector 对于我的需要来说似乎太复杂了).
Scala has all sorts sorts of immutable sequences like List, Vector,etc. I have been surprised to find no implementation of immutable indexed sequence backed by a simple array (Vector seems way too complicated for my needs).
这有设计原因吗?我在邮件列表上找不到很好的解释.
Is there a design reason for this? I could not find a good explanation on the mailing list.
对于性能与数组接近的不可变索引序列，您有什么建议吗?我正在考虑使用 scalaz 的 ImmutableArray，但它有一些问题，例如 scala 主干.
Do you have a recommendation for an immutable indexed sequence that has close to the same performances as an array? I am considering scalaz's ImmutableArray, but it has some issues with scala trunk for example.
谢谢
推荐答案
您可以将数组转换为序列.
You could cast your array into a sequence.
val s: Seq[Int] = Array(1,2,3,4)
该数组将被隐式转换为 WrappedArray.由于类型是 Seq，更新操作将不再可用.
The array will be implicitly converted to a WrappedArray. And as the type is Seq, update operations will no longer be available.
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