问题描述
如何从我的Java代码中获取Maven project basedir（）？
How to get Maven project basedir() from my Java code?
推荐答案
根据，有一个maven属性 $ {basedir}
According to Codehaus, there's a maven property ${basedir}
如果您在资源中包含属性文件，该文件具有 $ {basedir} 占位符，并且，你会发现有一个构建时间替换将basedir放入属性文件中。然后，您可以使用代码中的属性实例加载它。
If you include a properties file in your resources, which has the ${basedir} placeholder, and enable filtering for the resources plugin, you will find that there's a build time substitution of the basedir into the properties file. You can then load this using a Properties instance in code.
在/ src / main / resources中，创建一个名为project.properties的文件，包含
in /src/main/resources, create a file called project.properties, containing
project.basedir=${basedir}
然后，在POM中，启用对/ src / main / resources的过滤，如上面链接的maven资源过滤文档中所述。
Then, in the POM, enable filtering for /src/main/resources, as outlined in the maven resources filtering documentation linked above.
然后，在代码中，在运行时，将属性文件加载到属性实例
Then, in code, at runtime, load the properties file into a Properties instance
Properties props = new Properties();
props.load(this.getClass().getResourceAsStream("project.properties"));
String basedir = props.get("project.basedir");
另一种方法是处理一些源文件并通过挂钩到<$ c来替换它们$ c> process-sources 阶段，但这不太容易解释。
An alternative would be to process some source files and do substitution in there by hooking into the process-sources phase, but that's not likely to be easy to explain.
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