如何缩放 mandelbrot 集

问题描述

我已经成功实现了维基百科文章中描述的 mandelbrot 集，但我不知道如何放大特定部分.这是我正在使用的代码:

I have successfully implemented the mandelbrot set as described in the wikipedia article, but I do not know how to zoom into a specific section. This is the code I am using:

+(void)createSetWithWidth:(int)width Height:(int)height Thing:(void(^)(int, int, int, int))thing
{
    for (int i = 0; i < height; ++i)
    for (int j = 0; j < width; ++j)
    {
        double x0 = ((4.0f * (i - (height / 2))) / (height)) - 0.0f;
        double y0 = ((4.0f * (j - (width / 2))) / (width)) + 0.0f;
        double x = 0.0f;
        double y = 0.0f;

        int iteration = 0;
        int max_iteration = 15;

        while ((((x * x) + (y * y)) <= 4.0f) && (iteration < max_iteration))
        {
            double xtemp = ((x * x) - (y * y)) + x0;
            y = ((2.0f * x) * y) + y0;
            x = xtemp;
            iteration += 1;
        }

        thing(j, i, iteration, max_iteration);
    }
}

我的理解是 x0 应该在 -2.5 - 1 范围内，y0 应该在 -1 - 1 范围内，减少这个数字会放大，但这根本不起作用.如何缩放?

It was my understanding that x0 should be in the range -2.5 - 1 and y0 should be in the range -1 - 1, and that reducing that number would zoom, but that didnt really work at all. How can I zoom?

推荐答案

首先，如果 max_iteration 为 15，您将看不到太多细节.我的每个点有 1000 次迭代作为基线，并且可以进行大约 8000 次迭代，直到它真的变得太慢而无法等待.

first off, with a max_iteration of 15, you're not going to see much detail. mine has 1000 iterations per point as a baseline, and can go to about 8000 iterations before it really gets too slow to wait for.

这可能有帮助:http://jc.unternet.net/src/java/com/jcomeau/Mandelbrot.java

这也是:http://www.wikihow.com/Plot-the-Mandelbrot-Set-By-Hand

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