在 Swift 中进行十进制、二进制和十六进制之间的转换

问题描述

我想知道的是最高效的代码转换方式(在 swift 2 中):

What I want to know is the most code efficient way to convert (in swift 2):

• 十进制转二进制
• 二进制转十进制
• 十进制转十六进制
• 十六进制转十进制
• 二进制转十六进制
• 十六进制转二进制

我已经有了实现这一目标的基本且冗长的方法，但我想找到一种更有效的方法.

I already have a rudimentary and long-winded way of achieving this, but I would like to find a more efficient way.

推荐答案

String 和 Int 都具有采用 radix(基).结合这些，您可以实现所有转换:

Both String and Int have initializers which take a radix (base). Combining those, you can achieve all of the conversions:

// Decimal to binary
let d1 = 21
let b1 = String(d1, radix: 2)
print(b1) // "10101"

// Binary to decimal
let b2 = "10110"
let d2 = Int(b2, radix: 2)!
print(d2) // 22

// Decimal to hexadecimal
let d3 = 61
let h1 = String(d3, radix: 16)
print(h1) // "3d"

// Hexadecimal to decimal
let h2 = "a3"
let d4 = Int(h2, radix: 16)!
print(d4) // 163

// Binary to hexadecimal
let b3 = "10101011"
let h3 = String(Int(b3, radix: 2)!, radix: 16)
print(h3) // "ab"

// Hexadecimal to binary
let h4 = "face"
let b4 = String(Int(h4, radix: 16)!, radix: 2)
print(b4) // "1111101011001110"

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