本文介绍了我想要一个处理数据库的示例sencha触摸应用程序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是新来的触觉。我需要维护一个数据库(而不是本地存储)为sencha触摸应用程序,任何身体可以帮助我。解决方案
如果您使用php连接到mysql,这是一个简单的应用程序,我从sencha网站修改。
首先你的javascript
var helloWorld = new Ext.Application({
launch:function(){
Ext.regModel('Contacts',{
fields:[{
name:'first_last_name'
}]
});
store = new Ext.data.Store({
model:'Contacts',
proxy:{
type:'scripttag ',
url:'contact.php',
reader:{
type:'json',
root:'emergency_contact'
},
extraParams:{
action:'read'
}
}
});
var tmpl = new Ext 。模板(
'< table>',
'< tr>',
'< td>',
'{first_last_name}',
'< / td>',
'< / tr>',
'< / table>'
);
this.tabs = new Ext.TabPanel({
fullscreen:true,
dockedItems:[{
xtype:'toolbar',
title: 'Hello World'
}],
tabBar:{
ui:'light',
layout:{
pack:'center'
}
},
项目:[
{
html:'你好',
标题:'你好'
},
{
html:'world',
title:'world'
},
{
cls:'list',
title :'list',
xtype:'list',
store:store,
itemTpl:tmpl
}
]
});
this.list = this.tabs.items.getAt(2);
store.load();
}
});
然后在商店中声明contact.php
<?php
header('Content-Type:text / javascript; charset = UTF-8');
ini_set(display_errors,true);
ini_set(html_errors,true);
包含db_connect.php;
$ out =;
$ action =;
$ data =;
$ contact =;
if(isset($ _ REQUEST [action])){
$ action = $ _REQUEST [action];
}
switch($ action){
caseread:$ out = read_this();
break;
}
echo utf8_encode($ out);
函数read_this(){
$ conn = OpenDbConnection();
$ sql =从联系人中选择first_last_name;
$ result = mysql_query($ sql);
$ num = mysql_numrows($ result);
$ i = 0;
$ eData = array(count=> $ num,contact=> array());
while($ row = mysql_fetch_assoc($ result)){
$ eData [contact] [$ i] = $ row;
$ i ++;
}
CloseDbConnection($ conn);
// return json_encode($ eData);
返回$ _REQUEST ['callback']。 '('。json_encode($ eData)。');';
}
?>
然后使用PHP连接到数据库(db_connect)
<?php
function OpenDbConnection(){
$ dbhost ='localhost:3306';
$ dbuser ='phpapp';
$ dbpass ='phpapp';
$ dbname ='dbname';
$ conn = mysql_connect($ dbhost,$ dbuser,$ dbpass);
如果(!$ conn){
echo(无法连接到数据库服务器);
exit();
}
mysql_select_db($ dbname)or die(选择数据库时出错);
return $ conn;
}
函数CloseDbConnection($ conn){
mysql_close($ conn);
}
?>
这是一个sencha touch 1应用程序,但可以轻松修改以使用sencha touch 2.希望有助于
I am new to sencha touch. I have a requirement for maintaining a database (not local storage)for the sencha touch application, can any body help me.
解决方案
If your using php to connect to mysql this is a simple app I modified from the sencha site.
First your javascript
var helloWorld = new Ext.Application({
launch: function() {
Ext.regModel('Contacts', {
fields:[{
name:'first_last_name'
}]
});
store = new Ext.data.Store({
model: 'Contacts',
proxy: {
type: 'scripttag',
url: 'contact.php',
reader: {
type: 'json',
root: 'emergency_contact'
},
extraParams:{
action:'read'
}
}
});
var tmpl = new Ext.Template(
'<table>',
'<tr>',
'<td>',
'{first_last_name}',
'</td>',
'</tr>',
'</table>'
);
this.tabs = new Ext.TabPanel({
fullscreen: true,
dockedItems: [{
xtype:'toolbar',
title:'Hello World'
}],
tabBar: {
ui: 'light',
layout: {
pack: 'center'
}
},
items: [
{
html:'Hello',
title:'Hello'
},
{
html:'world',
title:'world'
},
{
cls: 'list',
title: 'list',
xtype: 'list',
store: store,
itemTpl:tmpl
}
]
});
this.list = this.tabs.items.getAt(2);
store.load();
}
});
And then contact.php declared in the store
<?php
header('Content-Type: text/javascript; charset=UTF-8');
ini_set("display_errors", true);
ini_set("html_errors", true);
include "db_connect.php";
$out = "";
$action = "";
$data = "";
$contact = "";
if (isset($_REQUEST["action"])) {
$action = $_REQUEST["action"];
}
switch ($action) {
case "read": $out = read_this();
break;
}
echo utf8_encode($out);
function read_this() {
$conn = OpenDbConnection();
$sql = "select first_last_name from contact";
$result = mysql_query($sql);
$num = mysql_numrows($result);
$i = 0;
$eData = array("count" => $num, "contact" => array());
while ($row = mysql_fetch_assoc($result)) {
$eData["contact"][$i] = $row;
$i++;
}
CloseDbConnection($conn);
// return json_encode($eData);
return $_REQUEST['callback'] . '(' . json_encode($eData) . ');';
}
?>
And then connecting to the database (db_connect) with php
<?php
function OpenDbConnection() {
$dbhost = 'localhost:3306';
$dbuser = 'phpapp';
$dbpass = 'phpapp';
$dbname = 'dbname';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if (!$conn) {
echo( "Unable to connect to the database server." );
exit();
}
mysql_select_db($dbname) or die( "Error selecting database.");
return $conn;
}
function CloseDbConnection($conn) {
mysql_close($conn);
}
?>
This a sencha touch 1 app but can easily be modified to work with sencha touch 2. Hope that helps
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