本文介绍了如何将JSONObject发送到改造API调用android的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
得到以下错误:java.lang.IllegalArgumentException:@Body参数不能与表单或多部分编码一起使用. (参数1)
getting following error : java.lang.IllegalArgumentException: @Body parameters cannot be used with form or multi-part encoding. (parameter #1)
我已经像下面那样实现了我的代码
I have implemented my code like below
public interface APIService {
@FormUrlEncoded
@POST("/")
@Headers({
"domecode: axys",
"Content-Type: application/json;charset=UTF-8"
})
Call<JsonObject> sendLocation(@Body JsonObject jsonObject);
}
public class ApiUtils {
static String tempUrl = "http://192.168.16.114:8092/api/v1/location/tsa/";
public static APIService getAPIService() {
return RetrofitClient.getClient(tempUrl).create(APIService.class);
}
}
public class RetrofitClient{
private static Retrofit retrofit = null;
public static Retrofit getClient(String baseUrl){
if(retrofit==null){
retrofit = new Retrofit.Builder()
.baseUrl(baseUrl)
.addConverterFactory(GsonConverterFactory.create())
.build();
}
return retrofit;
}
}
将值传递给API调用
JsonObject postParam = new JsonObject();
try {
postParam.addProperty(Fields.ID, "asdf");
}
Call<JsonObject> call = apiService.sendLocation(postParam);
call.enqueue(new Callback<JsonObject>() {
@Override
public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
Log.d("response","Getting response from server : "+response);
}
@Override
public void onFailure(Call<JsonObject> call, Throwable t) {
Log.d("response","Getting response from server : "+t);
}
}
);
推荐答案
您正在使用Android内部的Json API.您需要改用Gson的类.
You are using the Android internal Json APIs. You need to use Gson's classes instead.
Call<JsonObject> sendLocation(@Body JsonObject jsonObject);
因此导入语句
import com.google.gson.JsonObject;
另一个错误是将回调作为参数传递给请求
Another error is passing the Callback as a parameter to the request
Call<JsonObject> call = apiService.sendLocation(jsonObject);
call.enqueue(new Callback<JsonObject>() {
@Override
public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
Log.d("response","Getting response from server : "+response);
}
@Override
public void onFailure(Call<JsonObject> call, Throwable t) {
Log.d("response","Getting response from server : "+t);
}
});
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