问题描述
我在pylab模式下使用IPython(所有功能都在指尖)，并且想要注释某些绘图，比如说 plot([1,3,2])具有矩形((1,1),1,1)
I'm using IPython in pylab mode (all functions at fingertip), and wanted to annotate certain plot, lets say plot([1,3,2]) with rectangle Rectangle((1,1),1,1)
如何在pylab模式下绘制一个简单的矩形，即不使用图形，轴，子图...而是以最简单的方式引用刚刚创建的图
How can I draw a simple rectangle in this pylab mode, that is without using figure, axes, subplots... but reference just created plot in easiest possible way
推荐答案
pylab框架中也存在变形，轴和子图.如果我使用的是 pylab 界面，我只需在其中抛出一个 subplot(111)，然后使用 sp.add_patch(Rectangle(etc)).但是您也可以使用 gca()和 gcf()来获取当前轴/图形:
Figues, axes, and subplots exist in the pylab framework too. If I were using the pylab interface, I'd simply throw a subplot(111) in there and then use sp.add_patch(Rectangle(etc)). But you can also grab the current axes/figure using gca() and gcf():
>>> from pylab import *
>>> plot([1,3,2])
[<matplotlib.lines.Line2D object at 0x102bc8950>]
>>> gca()
<matplotlib.axes.AxesSubplot object at 0x102790cd0>
>>> gca().add_patch(Rectangle((1,1),1,1))
<matplotlib.patches.Rectangle object at 0x102790510>
>>> savefig("rect.png")
pylab 方法对于非常基本的任务来说足够简单，但不能很好地扩展到更复杂的任务.
The pylab approach is simple enough for very basic tasks, but doesn't scale as well up to more complex ones.
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