本文介绍了如何将XML数据放入列表视图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试在列表视图中获取xml数据,以下是我正在使用的

i am trying to fetch xml data in listview,following is the i am using

//code for parsing xml data//

import java.io.IOException;
import java.io.StringReader;
import java.io.UnsupportedEncodingException;
import java.net.URL;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

import android.util.Log;
public class XMLParser{
public String getXmlFromUrl(String url) {
    String xml = null;

    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost("http://itemsongs/assets/xml/itemsong_main.xml");

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        xml = EntityUtils.toString(httpEntity);

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    // return XML
    return xml;
	}
//GETTING DOCUMENT OBJECT MODEL ELEMENT
public Document getDomElement(String xml){
    Document doc = null;
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    try {

        DocumentBuilder db = dbf.newDocumentBuilder();

        InputSource is = new InputSource();
            is.setCharacterStream(new StringReader(xml));
            doc = db.parse(is);

        } catch (ParserConfigurationException e) {
            Log.e("Error: ", e.getMessage());
            return null;
        } catch (SAXException e) {
            Log.e("Error: ", e.getMessage());
            return null;
        } catch (IOException e) {
            Log.e("Error: ", e.getMessage());
            return null;
        }
            // return DOM
        return doc;
	}

public String getValue(Element item, String str) {
    NodeList n = item.getElementsByTagName(str);
    return this.getElementValue(n.item(0));
}
//GETTING NODES 
public final String getElementValue( Node elem ) {
         Node child;
         if( elem != null){
             if (elem.hasChildNodes()){
                 for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){
                     if( child.getNodeType() == Node.TEXT_NODE  ){
                         return child.getNodeValue();
                     }
                 }
             }
         }
         return "";
  }


//All static variables
	static final String URL = "http://itemsongs/assets/xml/itemsong_main.xml";
//XML node keys
	static final String KEY_ITEM = "movie"; // parent node


	XMLParser parser = new XMLParser();
	String xml = parser.getXmlFromUrl("http://itemsongs/assets/xml/itemsong_main.xml"); // getting XML
	Document doc = parser.getDomElement(xml); // getting DOM element

	NodeList nl = doc.getElementsByTagName("movie");{

//looping through all item nodes <item>
		for (int i = 0; i < nl.getLength(); i++) {
			String name = parser.getValue(e, "KEY_NAME"); // name child value
			String cost = parser.getValue(e, "KEY_COST"); // cost child value
			String description = parser.getValue(e, "KEY_DESC"); // description child value
		}
	}
}
// i am getting error "e cannot be resolved to a variable" can anybody please suggest what should i do.


我正在将XMLParser代码与以下代码作为MainActivity一起使用,尽管我没有收到任何错误但该代码无法正常工作........请帮助,我完全迷路了...


i am using XMLParser code with the following code as MainActivity,though i am not getting any error but the code is not working..........please help ,i am completely lost...

//code for MainActivity.java//


import java.util.ArrayList;
import java.util.HashMap;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import android.app.ListActivity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;

public class MainActivity extends ListActivity {

    // All static variables
    static final String URL = "http://ishirsoft.com/itemsongs/assets/xml/itemsong_main.xml";
    // XML node keys
    static final String KEY_ITEM = "movie"; // parent node


    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        ArrayList<hashmap><string,>> menuItems = new ArrayList<hashmap><string,>>();

        XMLParser parser = new XMLParser();
        String xml = parser.getXmlFromUrl("http://ishirsoft.com/itemsongs/assets/xml/itemsong_main.xml"); // getting XML
        Document doc = parser.getDomElement(xml); // getting DOM element

        NodeList nl = doc.getElementsByTagName("movie");
        // looping through all item nodes <item>
        for (int i = 0; i < nl.getLength(); i++) {
            // creating new HashMap
            HashMap<string,> map = new HashMap<string,>();
            Element e = (Element) nl.item(i);
            // adding each child node to HashMap key => value
            map.put("name", parser.getValue(e, "name"));
           // map.put(KEY_NAME, parser.getValue(e, KEY_NAME));
           // map.put(KEY_COST, "Rs." + parser.getValue(e, KEY_COST));
           // map.put(KEY_DESC, parser.getValue(e, KEY_DESC));

            // adding HashList to ArrayList
            menuItems.add(map);
        }

        // Adding menuItems to ListView
        ListAdapter adapter = new SimpleAdapter(this, menuItems,
                R.layout.activity_main,
                new String[] { KEY_ITEM }, new int[] {
                       R.id.listView1 });

        setListAdapter(adapter);

        // selecting single ListView item
        ListView lv = getListView();
                // listening to single listitem click
        lv.setOnItemClickListener(new OnItemClickListener() {


            public void onItemClick(AdapterView                    int position, long id) {
                // getting values from selected ListItem
               // String name = ((TextView) view.findViewById(R.id.name)).getText().toString();
               // String cost = ((TextView) view.findViewById(R.id.cost)).getText().toString();
               // String description = ((TextView) view.findViewById(R.id.desciption)).getText().toString();

                // Starting new intent
            	Intent i= new Intent(MainActivity.this,XMLParser.class);
               // i.putExtra(KEY_ITEM, "movie");
                //in.putExtra(KEY_COST, cost);
               // in.putExtra(KEY_DESC, description);
                startActivity(i);

            }
        });
    }
}

推荐答案

RelativeLayout rl=(RelativeLayout) findViewById(R.id.rl);
ListView list=new ListView(this);

ArrayAdapter<charsequence> adp=ArrayAdapter.createFromResource(this,
                R.array.str, android.R.layout.simple_list_item_1);
adp.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
list.setAdapter(adp);
rl.addView(list); </charsequence>



我的xml文件:



My xml file :

<string-array name="str">
	    <item>List 1</item>
	    <item>List 2</item>
	    <item>List 3</item>
	    <item>List 4</item>
	</string-array>



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09-05 10:47
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