WPF - 选择基于一定条件下启动窗口

问题描述

我开发一个WPF应用程序用C＃和上午pretty的新的这个技术。我知道，当我点击运行，即按Ctrl + F5运行我的程序可以打开应用程序窗口，适当的小部件。我试图找出是否其可能基于一些检测条件，即打开不同的窗口，如果某些条件得到满足我想打开一个特定的窗口，但如果它不是我想要打开另一扇窗。

I am developing a WPF application with C#, and am pretty new to this technology. I know that when I run my program by clicking "Run" i.e "Ctrl + F5" it opens the application window with appropriate widgets. I am trying to find out if its possible to open different windows based on some check condition i.e if some condition is satisfied I wish to open a particular window, but if its not I want to open another window.

应该是这样打开的任何窗口之前，应该首先检查的条件像

It should be like before opening any window it should first check for the condition like

     if(File.Exists(<path-to-file>)
            Open Window 1
     else
            Open Window 2

这可能吗？

推荐答案

考虑的App.xaml

look into App.xaml

删除的StartupUri =MainWindow.xaml

添加启动=Application_Startup新的事件处理程序

<Application x:Class="YourProject.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             Startup="Application_Startup">

背后App.xaml.cs形式code创建Application_Startup像...

form code behind App.xaml.cs create Application_Startup like...

    private void Application_Startup(object sender, StartupEventArgs e)
    {
        //add some bootstrap or startup logic
        var identity = AuthService.Login();
        if (identity == null)
        {
            LoginWindow login = new LoginWindow();
            login.Show();
        }
        else
        {
            MainWindow mainView = new MainWindow();
            mainView.Show();
        }
    }

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